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											error C2665: 'PowerMod' : none of the 5 overloads can convert parameter 1 from type 'int'能帮我分析一下这个错误吗??
 
										
					
	 程序代码:
程序代码:    int bit=1024;
    unsigned char seeds[]="myseed";
    char errbuf[256];
    DSA *myDSA;            //定义DSA结构体
    myDSA = DSA_new();
    myDSA = DSA_generate_parameters(bit, seeds, 6, NULL, NULL, NULL, NULL);   //生成密钥参数
    if (myDSA == NULL) 
    {   
        unsigned long errorcode = ERR_get_error();
        ERR_error_string(errorcode, errbuf);
        printf("The error: %s", errbuf);
        return;
    }
      char *strp = BN_bn2dec(myDSA->p);          //将16进制转化为10进制
      char *strq = BN_bn2dec(myDSA->q);
      char *strg = BN_bn2dec(myDSA->g);
      ZZ m_q,m_g,m_p;
      m_p=to_ZZ(strp);
      m_q=to_ZZ(strq);
      m_g=to_ZZ(strg);
      cout<<endl;;
      cout<<"m_p="<<m_p<<"\n"<<endl;
      cout<<"m_q="<<m_q<<"\n"<<endl;  
      cout<<"m_g="<<m_g<<"\n"<<endl;   
      cout<<"按任意键继续\n"<<endl;  
      getch();
//……………………密钥计算部分…………………………
     
      ZZ xa,xb,ya,yb;
      xa=RandomBnd(m_q-1)+1;           //产生一个随机数,将其值赋给变量xa
      xb=RandomBnd(m_q-1)+1;
      ya=PowerMod(m_g,xa,m_p);          //计算对应公钥
      yb=PowerMod(m_g,xb,m_p);
      cout<<"Alice的私钥="<<xa<<endl;
      cout<<"按任意键计算Alice的公钥..."<<endl;
      getch();
      cout<<"Alice的公钥="<<ya<<"\n"<<endl;
      cout<<"Bob的私钥="<<xb<<endl;
      cout<<"按任意键计算Bob的公钥..."<<endl;
      getch();
      cout<<"Bob的公钥="<<yb<<"\n"<<endl;
      cout<<"…………密钥计算完毕…………\n"<<endl;
      getch();
这个怎么样