关于FOR循环的三级题
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[此贴子已经被作者于2005-1-8 20:42:02编辑过]
[此贴子已经被作者于2005-1-8 20:42:02编辑过]
int i, j1, j2;
for( i=0; i<100; i++) if(xx[i]) tntcon++;//统计数组xx[i]中的元素,存储在tntcon中 for( i=0; i<tnttcon; i++){ j1 = xx[i]%1000 ;//得到千位数字注意j1是整形 j2 = (xx[i]%100)/10;//得到十位数字 if ( j1%2!==0 && j2 % 2!==0)//如果千位和十位都是基数 { tcncon += xx[i] ;//求和 cnt++;//统计数目(这里掉了括号) } } pingjun = tcncon/cnt//求均值 我加了注释,你再仔细想想,挺简单的