关于C语言自定义字符运算
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#include <stdio.h> float main(void) { float num1,num2,point; num1 = 1.02; num2 = 2.36; point = num1 + num2; printf("\n**********************************"); printf("\n**\t\t%.2f\t\t**\n",point); printf("**********************************"); return 0; }//想做的是用?,!替换以上代码中的num1,num2,实现!+?=3.36 请各位大神解答一下。