if("n % 2 == 1")//这个...
程序代码:#include <stdio.h>
int main(){
//用while循环求 1-1/2+1/3-1/4+1/5-1/6+........-1/100 的和
double i=1 ,sum=0;
int n=1;
do{
if(n%2==1)
sum =sum+1/i;
else
sum =sum-1/i;
n++;
i++;
}
while(n <= 100);
printf("%lf\n",sum);
return 0;
}[local]1[/local]