求教一下这个问题用c语言怎么实现的
矩阵P（2行3列）乘以 矩阵R（3行3列） 所得结果再 乘以 矩阵R，感谢解答！
2017-01-31 18:14
2017-01-31 19:22
程序代码：#include <stdio.h>
int main(void)
{
int p[2][3]= {{1,2,3},{4,5,6}},
r[3][3]= {{1,2,3},{4,5,6},{7,8,9}},
c[2][3];
int count,n,m,i;
for(i = 0; i < 2; i++)
{
for(m = 0; m < 3; m++)
{
for(n = 0,count = 0; n < 3; n++)
count += p[i][n]*r[n][m];
c[i][m] = count;
}
}
for(i = 0; i < 2; i++)
{
for(m = 0; m < 3; m++)
{
for(n = 0,count = 0; n < 3; n++)
count += c[i][n]*r[n][m];
p[i][m] = count;
}
}
for(n = 0; n < 2; n++)
{
for(m = 0; m < 3; m++)
printf("%d ",p[n][m]);
printf("\n");
}
return 0;
}[此贴子已经被作者于2017-1-31 19:49编辑过]
2017-01-31 19:32
2017-02-01 21:24
2017-02-01 21:26
2017-02-01 21:39
2017-02-01 22:24
程序代码：
#include <stdio.h>
int main(void)
{
int p[2][3]= {{1,2,3},{4,5,6}},
r[3][3]= {{1,2,3},{4,5,6},{7,8,9}},
c[2][3];
int count,n,m,i;
int N = 5;
while(N--)
{
for(i = 0; i < 2; i++)
{
for(m = 0; m < 3; m++)
{
for(n = 0,count = 0; n < 3; n++)
count += p[i][n]*r[n][m];
c[i][m] = count;
}
}
for(i = 0; i < 2; i++)
{
for(m = 0; m < 3; m++)
{
for(n = 0,count = 0; n < 3; n++)
count += c[i][n]*r[n][m];
p[i][m] = count;
}
}
for(n = 0; n < 2; n++)
{
for(m = 0; m < 3; m++)
printf("%d ",p[n][m]);
printf("\n");
}
return 0;
}[此贴子已经被作者于2017-2-1 23:56编辑过]
2017-02-01 22:35
2017-02-01 23:44
