新人请教程序错在哪，用户输入数据后，就没有输出了 - C语言论坛

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标题：新人请教程序错在哪，用户输入数据后，就没有输出了

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tximist

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楼主

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新人请教程序错在哪，用户输入数据后，就没有输出了

题目要求：

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代码：

程序代码：

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    #define DEPART_TIME_1 (8 * 60)

    #define DEPART_TIME_2 (9 * 60 + 43)

    #define DEPART_TIME_3 (11 * 60 + 19)

    #define DEPART_TIME_4 (12 * 60 + 47)

    #define DEPART_TIME_5 (14 * 60)

    #define DEPART_TIME_6 (15 * 60 + 45)

    #define DEPART_TIME_7 (19 * 60)

    #define DEPART_TIME_8 (21 * 60 + 45)

    int h, m, user_time, min;

    printf("Enter a 24-hour time(h:m): ");

    scanf("%d:%d", &h, &m);

    user_time = h * 60 + m;

    min = (abs(user_time - DEPART_TIME_1) < abs(user_time - DEPART_TIME_2)) ? abs(user_time - DEPART_TIME_1) : abs(user_time - DEPART_TIME_2);

    min = (min < abs(user_time - DEPART_TIME_3)) ? min : abs(user_time - DEPART_TIME_3);

    min = (min < abs(user_time - DEPART_TIME_4)) ? min : abs(user_time - DEPART_TIME_4);

    min = (min < abs(user_time - DEPART_TIME_5)) ? min : abs(user_time - DEPART_TIME_5);

    min = (min < abs(user_time - DEPART_TIME_6)) ? min : abs(user_time - DEPART_TIME_6);

    min = (min < abs(user_time - DEPART_TIME_7)) ? min : abs(user_time - DEPART_TIME_7);

    min = (min < abs(user_time - DEPART_TIME_8)) ? min : abs(user_time - DEPART_TIME_8);

    switch (user_time - min)
    {
        case DEPART_TIME_1:
            printf("Closest departure time is 8:00 a.m., arriving at 10:16 a.m.");
            break;
        case DEPART_TIME_2:
            printf("Closest departure time is 9:43 a.m., arriving at 11:52 a.m.");
            break;
        case DEPART_TIME_3:
            printf("Closest departure time is 11:19 a.m., arriving at 1:31 p.m.");
            break;
        case DEPART_TIME_4:
            printf("Closest departure time is 12:47 p.m., arriving at 3:00 p.m.");
            break;
        case DEPART_TIME_5:
            printf("Closest departure time is 2:00 p.m., arriving at 4:08 p.m.");
            break;
        case DEPART_TIME_6:
            printf("Closest departure time is 3:45 p.m., arriving at 5:55 p.m.");
            break;
        case DEPART_TIME_7:
            printf("Closest departure time is 7:00 p.m., arriving at 9:20 p.m.");
            break;
        case DEPART_TIME_8:
            printf("Closest departure time is 9:45 p.m., arriving at 11:58 p.m.");
            break;
    }

    return 0;
}

屏幕输出：

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输入9：00后，就没有第二步输出了，请问哪个地方有问题？

[ 本帖最后由 tximist 于 2015-9-20 17:03 编辑 ]

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2015-09-20 16:58

林月儿

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点值和区间值匹对。。。

剑栈风樯各苦辛，别时冰雪到时春

2015-09-20 17:18

tximist

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第 3 楼

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回复 2楼林月儿

可否详解？不是很明白，switch表达式？case表达式？还是啥地方？

2015-09-20 17:22

林月儿

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以下是引用tximist在2015-9-20 17:22:23的发言：

可否详解？不是很明白，switch表达式？case表达式？还是啥地方？

switch判断对象应该是连续型数值
判断分支则是点值

剑栈风樯各苦辛，别时冰雪到时春

2015-09-20 17:26

小王KING

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第 5 楼

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9：00，输入
  switch (user_time - min)   //这里的结果是8*60+17，你说他跟下面个那个值匹配？
、
min = (abs(user_time - DEPART_TIME_1) < abs(user_time - DEPART_TIME_2)) ? abs(user_time - DEPART_TIME_1) : abs(user_time - DEPART_TIME_2);

    min = (min < abs(user_time - DEPART_TIME_3)) ? min : abs(user_time - DEPART_TIME_3);

    min = (min < abs(user_time - DEPART_TIME_4)) ? min : abs(user_time - DEPART_TIME_4);

    min = (min < abs(user_time - DEPART_TIME_5)) ? min : abs(user_time - DEPART_TIME_5);

    min = (min < abs(user_time - DEPART_TIME_6)) ? min : abs(user_time - DEPART_TIME_6);

    min = (min < abs(user_time - DEPART_TIME_7)) ? min : abs(user_time - DEPART_TIME_7);

    min = (min < abs(user_time - DEPART_TIME_8)) ? min : abs(user_time - DEPART_TIME_8);
//上面7条语句，在比较的时候，要用绝对值比较，才能获得最接近的时间，返回时间差的时候，要获得真实值。例如min=(abs(x)<abs(y))?x,y;
//修改如下
min = (abs(user_time - DEPART_TIME_1) < abs(user_time - DEPART_TIME_2)) ? (user_time - DEPART_TIME_1) :(user_time - DEPART_TIME_2);

    min = (abs(min) < abs(user_time - DEPART_TIME_3)) ? min : (user_time - DEPART_TIME_3);

    min = (abs(min) < abs(user_time - DEPART_TIME_4)) ? min : (user_time - DEPART_TIME_4);

    min = (abs(min) < abs(user_time - DEPART_TIME_5)) ? min : (user_time - DEPART_TIME_5);

    min = (abs(min) < abs(user_time - DEPART_TIME_6)) ? min : (user_time - DEPART_TIME_6);

    min = (abs(min) < abs(user_time - DEPART_TIME_7)) ? min : (user_time - DEPART_TIME_7);

    min = (abs(min) < abs(user_time - DEPART_TIME_8)) ? min : (user_time - DEPART_TIME_8);

2015-09-20 17:32

tximist

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以下是引用林月儿在2015-9-20 17:26:58的发言：

switch判断对象应该是连续型数值
判断分支则是点值

有无具体例子，或如何修改程序？

2015-09-20 17:35

林月儿

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第 7 楼

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程序代码：

#include <stdio.h>
#include <stdlib.h>
#define DEPART_TIME_1 (8 * 60)

#define DEPART_TIME_2 (9 * 60 + 43)

#define DEPART_TIME_3 (11 * 60 + 19)

#define DEPART_TIME_4 (12 * 60 + 47)

#define DEPART_TIME_5 (14 * 60)

#define DEPART_TIME_6 (15 * 60 + 45)

#define DEPART_TIME_7 (19 * 60)

#define DEPART_TIME_8 (21 * 60 + 45)
int main(void)
{
    
    int a[8]={8 * 60,9 * 60 + 43,11 * 60 + 19,12 * 60 + 47,14 * 60,15 * 60 + 45,19 * 60,21 * 60 + 45} ;
    int h, m, user_time,i;
    
    for(printf("Enter a 24-hour time(h:m): ");
           scanf("%d:%d", &h, &m)!=2 ;
           scanf("%*[^\n]"), printf("%s","Exception: data format , try again: "));

    user_time = h * 60 + m;
    for(i=0;i<7;i++)
        if(a[i]<user_time&&a[i+1]>user_time)break;
    switch (a[i])
    {
        case DEPART_TIME_1:
            printf("Closest departure time is 8:00 a.m., arriving at 10:16 a.m.");
            break;
        case DEPART_TIME_2:
            printf("Closest departure time is 9:43 a.m., arriving at 11:52 a.m.");
            break;
        case DEPART_TIME_3:
            printf("Closest departure time is 11:19 a.m., arriving at 1:31 p.m.");
            break;
        case DEPART_TIME_4:
            printf("Closest departure time is 12:47 p.m., arriving at 3:00 p.m.");
            break;
        case DEPART_TIME_5:
            printf("Closest departure time is 2:00 p.m., arriving at 4:08 p.m.");
            break;
        case DEPART_TIME_6:
            printf("Closest departure time is 3:45 p.m., arriving at 5:55 p.m.");
            break;
        case DEPART_TIME_7:
            printf("Closest departure time is 7:00 p.m., arriving at 9:20 p.m.");
            break;
        case DEPART_TIME_8:
            printf("Closest departure time is 9:45 p.m., arriving at 11:58 p.m.");
            break;
    }

    return 0;
}

剑栈风樯各苦辛，别时冰雪到时春

2015-09-20 17:59

tximist

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以下是引用林月儿在2015-9-20 17:59:30的发言：

#include
#include
#define DEPART_TIME_1 (8 * 60)

#define DEPART_TIME_2 (9 * 60 + 43)

#define DEPART_TIME_3 (11 * 60 + 19)

#define DEPART_TIME_4 (12 * 60 + 47)

#define DEPART_TIME_5 (14 * 60)

#define DEPART_TIME_6 (15 * 60 + 45)

#define DEPART_TIME_7 (19 * 60)

#define DEPART_TIME_8 (21 * 60 + 45)
int main(void)
{

    int a[8]={8 * 60,9 * 60 + 43,11 * 60 + 19,12 * 60 + 47,14 * 60,15 * 60 + 45,19 * 60,21 * 60 + 45} ;
    int h, m, user_time,i;

    for(printf("Enter a 24-hour time(h:m): ");
           scanf("%d:%d", &h, &m)!=2 ;
           scanf("%*[^\n]"), printf("%s","Exception: data format , try again: "));

    user_time = h * 60 + m;
    for(i=0;i<7;i++)
        if(auser_time)break;
    switch (a)
    {
        case DEPART_TIME_1:
            printf("Closest departure time is 8:00 a.m., arriving at 10:16 a.m.");
            break;
        case DEPART_TIME_2:
            printf("Closest departure time is 9:43 a.m., arriving at 11:52 a.m.");
            break;
        case DEPART_TIME_3:
            printf("Closest departure time is 11:19 a.m., arriving at 1:31 p.m.");
            break;
        case DEPART_TIME_4:
            printf("Closest departure time is 12:47 p.m., arriving at 3:00 p.m.");
            break;
        case DEPART_TIME_5:
            printf("Closest departure time is 2:00 p.m., arriving at 4:08 p.m.");
            break;
        case DEPART_TIME_6:
            printf("Closest departure time is 3:45 p.m., arriving at 5:55 p.m.");
            break;
        case DEPART_TIME_7:
            printf("Closest departure time is 7:00 p.m., arriving at 9:20 p.m.");
            break;
        case DEPART_TIME_8:
            printf("Closest departure time is 9:45 p.m., arriving at 11:58 p.m.");
            break;
    }

    return 0;
}

谢谢，研究研究，如果规定只用if if/else switch这些选择语句，如何写出来呢？

2015-09-20 18:33

林月儿

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以下是引用tximist在2015-9-20 18:33:23的发言：

谢谢，研究研究，如果规定只用if if/else switch这些选择语句，如何写出来呢？

if比较灵活，适用于区间范围值比较
switch形式简洁，应用范围有一定限制，只能是离散值
了解他们的特点加以利用进而优化代码即可

剑栈风樯各苦辛，别时冰雪到时春

2015-09-20 18:37

tximist

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以下是引用小王KING在2015-9-20 17:32:11的发言：

9：00，输入
  switch (user_time - min)   //这里的结果是8*60+17，你说他跟下面个那个值匹配？
、
min = (abs(user_time - DEPART_TIME_1) < abs(user_time - DEPART_TIME_2)) ? abs(user_time - DEPART_TIME_1) : abs(user_time - DEPART_TIME_2);

    min = (min < abs(user_time - DEPART_TIME_3)) ? min : abs(user_time - DEPART_TIME_3);

    min = (min < abs(user_time - DEPART_TIME_4)) ? min : abs(user_time - DEPART_TIME_4);

    min = (min < abs(user_time - DEPART_TIME_5)) ? min : abs(user_time - DEPART_TIME_5);

    min = (min < abs(user_time - DEPART_TIME_6)) ? min : abs(user_time - DEPART_TIME_6);

    min = (min < abs(user_time - DEPART_TIME_7)) ? min : abs(user_time - DEPART_TIME_7);

    min = (min < abs(user_time - DEPART_TIME_8)) ? min : abs(user_time - DEPART_TIME_8);
//上面7条语句，在比较的时候，要用绝对值比较，才能获得最接近的时间，返回时间差的时候，要获得真实值。例如min=(abs(x)

刚开始，我是想user_time - min这个跟宏定义值DEPART_TIME_2 (9 * 60 + 43)匹配，因为user_time - min == user_time - user_time - DEPART_TIME_2 == DEPART_TIME_2

2015-09-20 18:49

快速回复：新人请教程序错在哪，用户输入数据后，就没有输出了