#include <ctype.h>
#include <stdio.h>

#define ALL_SUM 26
int main(void)
{
  int sum, j, i = 0, a[ALL_SUM] = {0};
  char ch;

  printf("Enter a word: ");

  while ((ch = getchar()) != '\n')
    switch (toupper(ch)) {
      case 'D': case 'G':
       a[i]= 2;  i++; break;
      case 'B': case 'C': case 'M': case 'P':
       a[i]= 3;  i++;  break;
      case 'F': case 'H': case 'V': case 'W': case 'Y':
       a[i]= 4;  i++;  break;
      case 'K':
       a[i]= 5;  i++;  break;
      case 'J': case 'X':
       a[i]= 8;  i++;  break;
      case 'Q': case 'Z':
       a[i]= 10;i++;  break;
      default:
       a[i] = 1; i++; break;
    }
  for (j = 0; j < i; j++)
       sum += a[i];
  printf("Scrabble value: %d\n", sum);

  return 0;
}

很简单的一个程序，输入字母，相应的转化为数字和。看下数组途中赋值出现了什么问题呢？初始化赋值为0，把后续赋值遮盖还是后面赋值本身就是错误？

简单说说：

#include <ctype.h>
#include <stdio.h>

#define ALL_SUM 26
int main(void)
{
  int sum=0, j, i = 0, a[ALL_SUM] = {0};
  


  char ch;

  printf("Enter a word: ");

  while ((ch = getchar()) != '\n')
    switch (toupper(ch)) {
      case 'D': case 'G':
       a[i]= 2;  i++; break;
      case 'B': case 'C': case 'M': case 'P':
       a[i]= 3;  i++;  break;
      case 'F': case 'H': case 'V': case 'W': case 'Y':
       a[i]= 4;  i++;  break;
      case 'K':
       a[i]= 5;  i++;  break;
      case 'J': case 'X':
       a[i]= 8;  i++;  break;
      case 'Q': case 'Z':
       a[i]= 10;i++;  break;
      default:
       a[i] = 1; i++; break;
    }
  for (j = 0; j < i; j++)
       sum += a[j];
  printf("Scrabble value: %d\n", sum);

  return 0;
}

原来如此