如何将字母A放在数组左上角第一个位置(随机分布)
编写程序,生成一种贯穿10*10字符数组的“随机分布”。A-Z
程序代码:#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#define MAXX 10
#define MAXY 10
int main()
{
int i =0, j = 0, count = 0;
char map[MAXX][MAXY];
const char str='A';
for (i=0; i<MAXX; i++)
{
for (j=0; j<MAXY; j++)
{
map[i][j]='.';
}
}
srand( (unsigned) time(NULL) );
i = rand()%MAXX;
j = rand()%MAXY;
while(1)
{
switch (rand()%4) //0、1、2、3分别代表上、下、左、右
{
case 0: if (i-1>=0 && map[i-1][j ]=='.')
{ map[i-1][j]=str+count;
count ++;
i -= 1;
} break;
case 1: if (i+1<=MAXX && map[i+1][j ]=='.')
{ map[i+1][j]=str+count;
count ++;
i += 1;
} break;
case 2: if (j-1>=0 && map[i ][j-1]=='.')
{ map[i][j-1]=str+count;
count ++;
j -= 1;
} break;
case 3: if (j+1<=MAXY && map[i ][j+1]=='.')
{ map[i][j+1]=str+count;
count ++;
j += 1;
} break;
}
if(count ==26) break;
}
for(i=0;i<10;++i)
{
for(j=0;j<10;++j)
printf("%c ",map[i][j]);
printf("\n");
}
return 0;
}
搞了好久,求教








