大神求教：循环移位程序的分析
程序代码：#include<stdio.h>
int right(unsigned value,int n);
int left(unsigned value,int n);
int right(unsigned value,int n){
unsigned z;
z=(value>>n)|(value<<(16-n));
return z;
}
int left(unsigned value,int n){
unsigned z;
z=(value>>(16-n))|(value<<n);
return z;
}
int main(){
unsigned a;
int n;
printf("input:\n");
scanf("%o",&a);
printf("input:\n");
scanf("%d",&n);
if(n>0){
right(a,n);
printf("the result is:%o\n",right(a,n));
}
else{
n=-n;
left(a,n);
printf("the result is :%o\n",left(a,n));
}
return 0;
}
以其中向右移动的函数为例。
z=(value>>n)|(value<<(16-n));
这句话给解释一下吧。举例子说明一下就行
