程序代码：

#include<stdio.h>
#include<math.h>

double lagechazhi(double *a,double *b,double x,int n)
{
    int i,j; double sum,SUM=0;
    for(i=0;i<n;i++)
    {
        sum=1;
        for(j=0;j<n;j++)
        {
            if(j!=i)
                sum=sum*(x-a[j])/(a[i]-a[j]);
        }
        SUM=SUM+sum*b[i];
    }
    printf(" SUM=%d\n",SUM);//...............在此处设置断点显示的只是3.053多但是经printf输出为-183144；
    return SUM;
}

void main()
{
    double a[3]={1,1.05,1.07},b[3]={2.71828,3.28630,3.52761};
    lagechazhi(a,b,1.03,3);


}