JAVA逻辑编程题,真心做不出来,麻烦大家了
A、B、C、D、E五位同学各自从不同的途径打听到获得通讯赛第一名的同学的情况:A:姓李,女同学,年龄13,广东人
B:姓张,男同学,年龄11,湖南人
C:姓陈,女同学,年龄13,广东人
D:姓黄,男同学,年龄11,广西人
E:姓张,男同学,年龄12,广东人
实际上,获得第一名的同学姓什么,性别,年龄,哪里人这四项情况在表中已有,但五位同学所打听到的情况,每人仅有一项是正确的。
请根据此推断获得第一名的同学的情况。
程序代码:
import java.util.*;
public class FirstStudent {
private static String[] infoArray = {
"姓李,女同学,年龄13,广东人", // A
"姓张,男同学,年龄11,湖南人", // B
"姓陈,女同学,年龄13,广东人", // C
"姓黄,男同学,年龄11,广西人", // D
"姓张,男同学,年龄12,广东人", // E
};
// InfoSet
private static Set<String> nameSet = new TreeSet<>();
private static Set<String> sex_Set = new TreeSet<>();
private static Set<String> age_Set = new TreeSet<>();
private static Set<String> homeSet = new TreeSet<>();
public static void main(String[] args) {
for (String infoString : infoArray) {
initInfoSet(infoString);
}
for (String name : nameSet) {
for (String sex : sex_Set) {
for (String age : age_Set) {
for (String home : homeSet) {
if(meetCondition(name, sex, age, home, infoArray[0], 0)
&& meetCondition(name, sex, age, home, infoArray[1], 0)
&& meetCondition(name, sex, age, home, infoArray[2], 0)
&& meetCondition(name, sex, age, home, infoArray[3], 0)
&& meetCondition(name, sex, age, home, infoArray[4], 0)) {
System.out.println(
"第一名的同学:"
+ name + ","
+ sex + ","
+ age + ","
+ home);
}
}
}
}
}
}
private static void initInfoSet(String infoString) {
nameSet.add(infoString.split(",")[0]);
sex_Set.add(infoString.split(",")[1]);
age_Set.add(infoString.split(",")[2]);
homeSet.add(infoString.split(",")[3]);
}
private static boolean meetCondition(
String nameString,
String sex_String,
String age_String,
String homeString,
String infoString,
int meetTimes) {
meetTimes = nameString.equals(infoString.split(",")[0]) ? meetTimes + 1 : meetTimes;
meetTimes = sex_String.equals(infoString.split(",")[1]) ? meetTimes + 1 : meetTimes;
meetTimes = age_String.equals(infoString.split(",")[2]) ? meetTimes + 1 : meetTimes;
meetTimes = homeString.equals(infoString.split(",")[3]) ? meetTimes + 1 : meetTimes;
return (meetTimes == 1); // 每人仅有一项是正确的
}
}