c语言求三个数中的最大值和最小值 的算法

#include<stdio.h>

int main(void)
{
   int x1, x2, x3, max, min;
   scanf("%d%d%d", &x1, &x2, &x3);
  
   if(x1 > x2 && x1 > x3)
     if(x2 > x3)
         min = x3;
     else 
         min = x2;
         max = x1;
  
   if(x2 > x1 && x2 > x3)
     if(x1 > x3)
         min = x3;
     else 
         min = x1;
         max = x2;
  
   if(x3 > x2 && x3 > x1)
     if(x2 > x1)
         min = x1;
     else 
         min = x2;
         max = x3;
  
   printf("max = %d\nmin = %d\n", max, min);
}

试试这个！
#include <stdio.h>

int main()
{
    int a = 2, b = 1, c = 3, t;
    if(a > b) {t = a; a = b; b = t;}
    if(a > c) {t = a; a = c; c = t;}
    if(b > c) {t = b; b = c; c = t;}
    printf("%d %d\n", a , c);
    return 0;
}

..1

#include<stdio.h>
int main()
{int a,b,c;
 scanf("%d%d%d",&a,&b,&c);
 if(a>b)
   if(b>c)
    printf("%d%d%d",a,b,c);
   else
    if(a>c)
    printf("%d%d%d",a,c,b);
    else
    printf("%d%d%d",c,a,b);

 else
   if(a>c)
    printf("%d%d%d",b,a,c);
    if(b>c)
    printf("%d%d%d",b,c,a);
    else
    printf("%d%d%d",c,b,a);
return 0;
}
方法很多，多多交流

设2个变量max和min分别存放每次比较后的最大值和最小值，最后输出就行

试试这个感觉比较简单
#include<stdio.h>
int main()
{
    int a,b,c,max,min;
    printf("输入3个数:\n");
    scanf("%d%d%d",&a,&b,&c);
    max=a;
    if(max<b)max=b;
    if(max<c)max=c;
    min=a;
    if(min>b)min=b;
    if(min>c)min=c;
    printf("最大值:%d,最小值:%d\n",max,min);
}

厉害了