c语言程序设计中二叉树例子的疑惑<已解决>
程序代码:#include <stdio.h>
#include <ctype.h>
#include <string.h>
#include <stdlib.h>
#define MAXWORD 100
struct tnode { /* the tree node: */
char *word; /* points to the text */
int count; /* number of occurrences */
struct tnode *left; /* left child */
struct tnode *right; /* right child */
};
struct tnode *addtree(struct tnode *, char *);
void treeprint(struct tnode *);
int getword(char *, int);
/* word frequency count */
main()
{
char c;
struct tnode *root;
char word[MAXWORD];
root = NULL;
while (scanf("%s",word)!=EOF)
root = addtree(root, word);//这里不太理解,root作为根节点要是被更改了,下次操作时又怎么找到根节点呢?
treeprint(root);
return 0;
}
struct tnode *talloc(void);
char *strdup(char *);
/* addtree: add a node with w, at or below p */
struct tnode *addtree(struct tnode *p, char *w)
{
int cond;
if (p == NULL) { /* a new word has arrived */
p = talloc(); /* make a new node */
p->word = strdup(w);
p->count = 1;
p->left = p->right = NULL;
} else if ((cond = strcmp(w, p->word)) == 0)
p->count++; /* repeated word */
else if (cond < 0) /* less than into left subtree */
p->left = addtree(p->left, w);
else /* greater than into right subtree */
p->right = addtree(p->right, w);
return p;
}
/* treeprint: inorder
print of tree p */
void treeprint(struct tnode *p)
{
if (p != NULL) {
treeprint(p->left);
printf("%d %s\n", p->count, p->word);
treeprint(p->right);
}
}
/* talloc: make a tnode */
struct tnode *talloc(void)
{
return (struct tnode *) malloc(sizeof(struct tnode));
}
char *strdup(char *s) /* make a duplicate of s */
{
char *p;
p = (char *) malloc(strlen(s)+1); /* +1 for '\0' */
if (p != NULL)
strcpy(p, s);
return p;
}问题:
main函数里面
root = addtree(root, word)
roo作为根节点每次都被赋了新值,下次又是如何找到根节点的呢
实际运行没有错误
请各位高手指点一下
[ 本帖最后由 阿的个发 于 2012-5-12 20:43 编辑 ]






