程序代码：

#include< stdio.h >
#include< stdlib.h >
int
    main( void )
{
    int f[] = {1,3,5,7,9};
    int g[] = {2,3,4,7,8};
    int k;
    int t( int f[],int g[],int m,int n )
        m = sizeof(f[]);
        n = sizeof(g[]);
        k = t( f[],g[],m,n );
        printf( "%d",k);
        system( "pause" );
}

int
    t( int f[], int g[], int m,int n )
{
    int a, b, count;
    count = a = b = 0;
    while( a < m && b < n )
    {
        if( f[a] <= g[b] )
            a++;
        else
            b++, count += m - a;
        return count
    }
}

运行不了，
我改成下面的来是一样


























#include< stdio.h >
#include< stdlib.h >
int
    main( void )
{
    int f[] = {1,3,5,7,9};
    int g[] = {2,3,4,7,8};
    int k;
    int m = 5;
    int n = 5;
    int t( int f[],int g[],int m,int n )
        k = t( f[],g[],m,n );
        printf( "%d",k);
        system( "pause" );
}

int
    t( int f[], int g[], int m,int n )
{
    int a, b, count;
    count = a = b = 0;
    while( a < m && b < n )
    {
        if( f[a] <= g[b] )
            a++;
        else
            b++, count += m - a;
        return count
    }
}

程序代码：

#include< stdio.h >
#include< stdlib.h >
int main( void )
{
    int f[] = {1,3,5,7,9};
    int g[] = {2,3,4,7,8};
    int k;
    int m = 5;
    int n = 5;
    int t( int f[],int g[],int m,int n );
    k = t( f,g,m,n );
    printf( "%d",k);
    system( "pause" );
     return 1;
}

int t( int f[], int g[], int m,int n )
{
    int a, b, count;
    count = a = b = 0;
    while( a < m && b < n )
    {
        if( f[a] <= g[b] )
            a++;
        else
            b++, count += m - a;
        return count;
    }
     return count;
}