#include <stdio.h>
#include <string.h>

#define LENGTH 20

typedef struct SqList
{
    char name[LENGTH];
    struct SqList *next;
}SqList;

/*链表的初始化和输出*/
SqList *InitSqList(SqList *h);
void ShowList(SqList *h);

int main()
{
    SqList *head = NULL;
    head = InitSqList(head);
    ShowList(head);
    return 0;
}

/*链表的初始化*/
SqList *InitSqList(SqList *h)
{
    SqList *p1, *p2;
    p1 = p2 = (SqList *)malloc(sizeof(SqList));
    scanf("%s", p2->name);
    p2 = p2->next;
    while(!strcmp(p2->name, "#"))
    {
        if(h = NULL)
        {
            h = p2;
        }
        else
        {
            p1->next = p2;
        }
        p1 = p2;
        p2 = (SqList*)malloc(sizeof(SqList));
        if(p2 != NULL)
        {
            scanf("%s", p2->name);
            p2 = p2->next;
        }
    }
    p2->next = NULL;
    return h;
}

/*链表的输出*/
void ShowList(SqList *h)
{
    SqList *temp = h;
    while (temp->next != NULL)
    {
        printf("%s\t", temp->name);
        temp = temp->next;
    }
}

错得很明显，所以这里我就解释错在哪儿了

什么不好意思的，哪个不是这么过来的

#include <stdio.h>
#include <string.h>

#define LENGTH 20

typedef struct SqList
{
    char name[LENGTH];
    struct SqList *next;
}SqList;

/*链表的初始化和输出*/
SqList *InitSqList(SqList *h);
void ShowList(SqList *h);

int main()
{
    SqList *head = NULL;
    head = InitSqList(head);
    ShowList(head);
    system("pause");
    return 0;
}

/*链表的初始化*/
SqList *InitSqList(SqList *h)
{
    SqList *p1, *p2;
    while(1)
    {
        p2 = (SqList *)malloc(sizeof(SqList));
        scanf("%s", p2->name);
        if(strcmp(p2->name,"#") == 0)
        {
              break;
        }
        else
        {
            if(h == NULL) //<-----这里是==
            {
                 p2->next = NULL; //尾节点的next指针都等于NULL，这个你都漏了
                 h = p2;
                 p1 = p2;
            }
            else
            {
                 p1->next = p2;
                 p2->next = NULL;
                 p1 = p2;
            }
        }
    }
    return h;
}

/*链表的输出*/
void ShowList(SqList *h)
{
    SqList *temp = h;
    while (temp != NULL)  //<----- 按你的写法就会缺失最后一个节点
    {
        printf("%s\n", temp->name);
        temp = temp->next;
    }
}

 

谢谢，已经改好了！

/*
========================================================
我又改了下，改成这样子。编译的时候出现了两个警告
警告说temp->next = next和p1->next = p2;出现了
“不兼容的任务分配”
warning: assignment from incompatible pointer type
这是什么原因呢？
但是在typedef struct 后面加上SqList，警告就没了
=======================================================
*/
#include <stdio.h>
#include <stdlib.h>

#define LENGTH 20

typedef struct
{
    char name[LENGTH];
    struct SqList *next;
}SqList;

/*链表的初始化和输出*/
SqList *InitSqList(SqList *h);
void ShowList(SqList *h);

int main()
{
    SqList *head = NULL;
    head = InitSqList(head);
    ShowList(head);
    return 0;
}

/*链表的初始化*/
SqList *InitSqList(SqList *h)
{
    SqList *p1, *p2;
    p1 = p2 = (SqList *)malloc(sizeof(SqList));
    scanf("%s", p2->name);
    getchar();
    p2->next = NULL;
    while(p2->name[0] != '#')
    {
        if(h == NULL)
        {
            h = p2;
        }
        else
        {
            p1->next = p2;
        }
        p1 = p2;
        p2 = (SqList*)malloc(sizeof(SqList));
        if(p2 != NULL)
        {
            scanf("%s", p2->name);
            p2->next = NULL;
        }
    }
    p2->next = NULL;
    return h;
}

/*链表的输出*/
void ShowList(SqList *h)
{
    SqList *temp = h;
    while (temp != NULL)
    {
        printf("%s\n", temp->name);
        temp = temp->next;
    }
}

[ 本帖最后由 thlgood 于 2011-4-16 17:29 编辑 ]

木有人回复啊，自己顶上去

你链表类型没有定义

#include <stdio.h>
#include <stdlib.h>

#define LENGTH 20

struct SqList  
 {
     char name[LENGTH];
     struct SqList *next;
 }SqList;

typedef struct SqList SqList ;

/*链表的初始化和输出*/
 SqList *InitSqList(SqList *h);
void ShowList(SqList *h);

int main()
 {
     SqList *head = NULL;
     head = InitSqList(head);
     ShowList(head);
     return 0;
 }

/*链表的初始化*/
 SqList *InitSqList(SqList *h)
 {
     SqList *p1, *p2;
     p1 = p2 = (SqList *)malloc(sizeof(SqList));
     scanf("%s", p2->name);
     getchar();
     p2->next = NULL;
     while(p2->name[0] != '#')
     {
         if(h == NULL)
         {
             h = p2;
         }
         else
         {
             p1->next = p2;
         }
         p1 = p2;
         p2 = (SqList*)malloc(sizeof(SqList));
         if(p2 != NULL)
         {
             scanf("%s", p2->name);
             p2->next = NULL;
         }
     }
     p2->next = NULL;
     return h;
 }

/*链表的输出*/
void ShowList(SqList *h)
 {
     SqList *temp = h;
     while (temp != NULL)
     {
         printf("%s\n", temp->name);
         temp = temp->next;
     }
 }

还想请教下：
为什么

while(p2->name[0] != '#')

改成

while (! strcmp (p2->name, "#"))

不行？

#include <stdio.h>
#include <string.h>
 #include <stdlib.h>

 #define LENGTH 20

 struct SqList  
 {
      char name[LENGTH];
      struct SqList *next;
 }SqList;

 typedef struct SqList SqList ;

 /*链表的初始化和输出*/
 SqList *InitSqList(SqList *h);
 void ShowList(SqList *h);

 int main()
 {
      SqList *head = NULL;
      head = InitSqList(head);
      ShowList(head);
      return 0;
 }

 /*链表的初始化*/
 SqList *InitSqList(SqList *h)
 {
      SqList *p1, *p2;
      p1 = p2 = (SqList *)malloc(sizeof(SqList));
      scanf("%s", p2->name);
      getchar();
      p2->next = NULL;
      while(strcmp(p2->name , "#"))
      {
          if(h == NULL)
          {
              h = p2;
          }
          else
          {
              p1->next = p2;
          }
          p1 = p2;
          p2 = (SqList*)malloc(sizeof(SqList));
          if(p2 != NULL)
          {
              scanf("%s", p2->name);
              p2->next = NULL;
          }
      }
      p2->next = NULL;
      return h;
 }

 /*链表的输出*/
 void ShowList(SqList *h)
 {
      SqList *temp = h;
      while (temp != NULL)
      {
          printf("%s\n", temp->name);
          temp = temp->next;
      }
 }

搞清楚strcmp的返回值

饿~~我错了！！