回复 8楼 canxden
											不简单										
					
	 程序代码:
程序代码:float a1,a2,answer;
        char op;
        scanf("%f%c%f",&a1,&op,&a2);
        if(op=='+'||op=='-'||op=='*'||op=='/')
        {switch(op) {
        case '+':answer=a1+a2;break;
        case '-':answer=a1-a2;break;
        case '*':answer=a1*a2;break;
        case '/':answer=a1/a2;break;
        }
        printf("Answer is %f\n",answer);}
        else printf("输入错误");