程序代码：

下面是关于做一个简单copy的代码，将参数一文件的内容复制到参数二文件上，代码一能够成功做实现，但代码二就不可以，参数一的内容怎么都复制不了到参数二上，不知哪里出了问题，能否给小弟指出,谢谢

代码一：

#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <stdio.h>
#include <errno.h>
#include <string.h>

char *myname;

int main(int argc, char **argv)
{
    int fda, fdd, wcount, rcount;
    char *wfile,*rfile;
    char buffer[BUFSIZ];
    myname = argv[0];
    if( argc < 3 ) {
        fprintf(stderr, "%s: not enough parameters \n",myname);
    }

    rfile = argv[1];
    wfile = argv[2];
   
    

    fda = open(rfile, O_RDONLY);
    rcount = read(fda, buffer, sizeof(buffer));

    fdd = open(wfile, O_RDWR|O_CREAT, 0666);
    wcount = write(fdd, buffer,rcount);
    if (wcount != rcount) {
        fprintf(stderr, "%s, %s: write err :%s\n",
            myname, wfile, strerror(errno));
    }
    (void)close(fda);
    (void)close(fdd);
    return (0);
}





代码二：
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <stdio.h>
#include <errno.h>
#include <string.h>

char *myname;

int main(int argc, char **argv)
{
    int fda, fdd, wcount, rcount;
    char *wfile,*rfile;
    char buffer[BUFSIZ];

      if( argc < 3 ) {
        fprintf(stderr, "%s: not enough parameters \n",myname);
    }


    myname = argv[0];
    rfile = argv[1];
    wfile = argv[2];
    

    if(fda = open(rfile, O_RDONLY) < 0) {
        fprintf(stderr, "%s: %s: cannot open for reading:%s\n",
                myname, rfile, strerror(errno));
        return 1;
    }
    rcount = read(fda, buffer, sizeof(buffer));

    if(fdd = open(wfile, O_RDWR|O_CREAT, 0666) < 0) {
        fprintf(stderr, "%s, %s: open fiel err :%s\n",
                myname, wfile,strerror(errno));
        return 1;   
    }
    wcount = write(fdd, buffer,rcount);
    if (wcount != rcount) {
        fprintf(stderr, "%s, %s: write err :%s\n",
            myname, wfile, strerror(errno));
    }
    (void)close(fda);
    (void)close(fdd);
    return (0);
}