求助代码跳转
我想实现验证正确就跳转到Log.html求解
程序代码:<script language="javascript" type="text/javascript">
function changeFocus()
{
if(event.srcElment.type!='button'&&
event.srcElment.type!='submit'&&
event.srcElment.type!='reset'&&
event.srcElment.type!='textarea'&&
event.srcElment.type!='')
event.keyCode=9;
}
document.onKeyDown=changeFocus;
function userName()
{
var name=document.userform.sname.value;
if(name.length<6||name.length>20)
{
alert("格式错误\n"+"请填写正确用户名");
}
return true;
}
function Password()
{
var Word=document.userform.pass.value;
if(Word.length<6||word.length>15)
{
alert("密码格式错误\n"+"6-15个字符");
}
return true;
}
function Rpassword()
{
var Word=document.userform.pass.value;
if(Word.length<6||word.length>15)
{
alert("密码必须相同");
}
return true;
}
function checkEmail()
{
var remail=document.userform.email.value;
if(remail.length==0)
{
alert("邮箱格式错误\n"+"请认真填写");
}
if(remail.indexof("@",0)==-1)
{
alert("邮箱地址必须包含'@'");
}
if(remail.indexof(".",0)==-1)
{
alert("邮箱必须包含'.'");
}
return true;
}
function validateform()
{
if(userName()&&Password()&&Rpassword()&&checkEmail())
return true;
if(true)
{
window.open("Log.html");
}
else
return false;
}
//
</script>









谢谢了2位了