一个五子棋程序，请教点问题
下面是我在一本实例书上看到的五子棋程序，看不是很懂，请教下高手：(1)m,n,t,s,flag,flak,z的意思
(2)判断方法，以判断前后为例讲一个就行了，
程序代码：case 1: /*判断前后数值是否与自己相同*/
while ((m1<=5)&&(flag1==0))
{
if(a[j][i+m1]/1==1)
{
m1=m1+1;
t1=t1+1;
printf("t1=%d \n",t1);
}
else flag1=1;
}
while ((n1<=5)&&(flak1==0))
{
if(a[j][i-n1]/1==1)
{
n1=n1+1;
s1=s1+1;
printf(" s1=%d \n",s1);
}
else flak1=1;
}
z1=s1+t1+1;
if(z1>=5)
{
p=W;
e=10;
}
break;
(3)觉得这程序有误或有改进的也希望提出来哈~~(4)附件是VC6.0编译出来的可执行文件：
五子棋.rar
(32.75 KB)
程序代码：/*
模拟五子棋游戏。以0表示空棋盘，其他数字表示游戏者以下的位置，A、B两个游戏者，输入棋子坐标指明落子位置。
*/
#include <stdio.h>
#include <math.h>
#define NUM1 5 /*改变棋盘的宽 要大于4*/
#define NUM2 5 /*改变棋盘的长 要大于4*/
#define W 27 /*比NUM1*NUM2+1大的数*/
#define V 28 /*比NUM1*NUM2+2大的数 W不能等于V */
main()
{
static int a[NUM1][NUM2],b[NUM1][NUM2],c[NUM1+1][NUM2+1];
/*c数组比a,b大一行和列作为坐标方便输入*/
int x,y,i,j,m,n,f=1,p=0;
int zuo_biaox=0,zuo_biaoy=0;
for(zuo_biaox=1; zuo_biaox<NUM1+1; zuo_biaox=zuo_biaox+1)
c[0][zuo_biaox]=zuo_biaox-1;
for(zuo_biaoy=1; zuo_biaoy<NUM2+1; zuo_biaoy=zuo_biaoy+1)
c[zuo_biaoy][0]=zuo_biaoy-1;
for(p=0; p<=NUM1*NUM2; p=p+1)
{
int e=1;
int m1=1,n1=1,t1=0,s1=0,flag1=0,flak1=0,z1=0;
int m2=1,n2=1,t2=0,s2=0,flag2=0,flak2=0,z2=0;
int m3=1,n3=1,t3=0,s3=0,flag3=0,flak3=0,z3=0;
int m4=1,n4=1,t4=0,s4=0,flag4=0,flak4=0,z4=0;
/*循环为棋盘变量赋值*/
f=-f;
if(f<0) printf("A: inputx&y:\n"); /*提示选手A下子*/
if(f>0) printf("B: inputx&y:\n"); /*提示选手B下子*/
scanf("%d %d", &x,&y );
if((x>=NUM2)||(y>=NUM1)) /*坐标不能超过棋盘格数*/
{
f=-f;
printf("the number is too big !\n");
/*如果输入数字太大超过棋盘格数*/
continue; /*跳出本次循环*/
}
if(c[y+1][x+1]!=0) /*已下棋的坐标不能再输入*/
{
f=-f;
printf("you can not put here!\n"); /*提示信息*/
continue; /*跳出本次循环*/
}
i=x;
j=y;
if(f<0)
{
c[j+1][i+1]=1;
c[0][0]=1;
}
if(f>0)
{
c[j+1][i+1]=2;
c[0][0]=2;
}
if(f<0) /*判断a 数组*/
{
a[j][i]=1;
for(e=1; e<=4; e=e+1)
{
switch(e)
{
case 1: /*判断前后数值是否与自己相同*/
while ((m1<=5)&&(flag1==0))
{
if(a[j][i+m1]/1==1)
{
m1=m1+1;
t1=t1+1;
printf("t1=%d \n",t1);
}
else flag1=1;
}
while ((n1<=5)&&(flak1==0))
{
if(a[j][i-n1]/1==1)
{
n1=n1+1;
s1=s1+1;
printf(" s1=%d \n",s1);
}
else flak1=1;
}
z1=s1+t1+1;
if(z1>=5)
{
p=W;
e=10;
}
break;
case 2: /*判断上下数值是否与自己相同*/
while ((m1<=5)&&(flag2==0))
{
if(a[j+m2][i]/1==1)
{
m2=m2+1;
t2=t2+1;
printf("t2=%d \n",t2);
}
else flag2=1;
}
while ((n2<=5)&&(flak2==0))
{
if(a[j-n2][i]/1==1)
{
n2=n2+1;
s2=s2+1;
printf(" s2=%d \n",s2);
}
else flak2=1;
}
z2=s2+t2+1;
if(z2>=5)
{
p=W;
e=10;
}
break;
case 3: /*判断右倾斜数值是否与自己相同*/
while ((m3<=5)&&(flag3==0))
{
if(a[j-m3][i+m3]/1==1)
{
m3=m3+1;
t3=t3+1;
printf("t3=%d \n",t3);
}
else flag3=1;
}
while ((n3<=5)&&(flak3==0))
{
if(a[j+n3][i-n3]/1==1)
{
n3=n3+1;
s3=s3+1;
printf(" s3=%d \n",s3);
}
else flak3=1;
}
z3=s3+t3+1;
if(z3>=5)
{
p=W;
e=10;
}
break;
case 4: /*判断左倾斜数值是否与自己相同*/
while ((m4<=5)&&(flag4==0))
{
if(a[j-m4][i-m4]/1==1)
{
m4=m4+1;
t4=t4+1;
printf("t4=%d \n",t4);
}
else flag4=1;
}
while ((n4<=5)&&(flak4==0))
{
if(a[j+n4][i+n4]/1==1)
{
n4=n4+1;
s4=s4+1;
printf(" s4=%d \n",s4);
}
else flak4=1;
}
z4=s4+t4+1;
if(z4>=5)
{
p=W;
e=10;
}
break;
}
}
}
if(f>0) /*判断b 数组*/
{
b[j][i]=2;
for(e=1; e<=4; e=e+1)
{
switch(e)
{
case 1: /*判断前后数值是否与自己相同*/
while ((m1<=5)&&(flag1==0))
{
if(b[j][i+m1]/2==1)
{
m1=m1+1;
t1=t1+1;
printf("t1=%d \n",t1);
}
else flag1=1;
}
while ((n1<=5)&&(flak1==0))
{
if(b[j][i-n1]/2==1)
{
n1=n1+1;
s1=s1+1;
printf(" s1=%d \n",s1);
}
else flak1=1;
}
z1=s1+t1+1;
if(z1>=5)
{
p=V;
e=10;
}
break;
case 2: /*判断上下数值是否与自己相同*/
while ((m1<=5)&&(flag2==0))
{
if(b[j+m2][i]/2==1)
{
m2=m2+1;
t2=t2+1;
printf("t2=%d \n",t2);
}
else flag2=1;
}
while ((n2<=5)&&(flak2==0))
{
if(b[j-n2][i]/2==1)
{
n2=n2+1;
s2=s2+1;
printf(" s2=%d \n",s2);
}
else flak2=1;
}
z2=s2+t2+1;
if(z2>=5)
{
p=V;
e=10;
}
break;
case 3: /*判断右倾斜数值是否与自己相同*/
while ((m3<=5)&&(flag3==0))
{
if(b[j-m3][i+m3]/2==1)
{
m3=m3+1;
t3=t3+1;
printf("t3=%d \n",t3);
}
else flag3=1;
}
while ((n3<=5)&&(flak3==0))
{
if(b[j+n3][i-n3]/2==1)
{
n3=n3+1;
s3=s3+1;
printf(" s3=%d \n",s3);
}
else flak3=1;
}
z3=s3+t3+1;
if(z3>=5)
{
p=V;
e=10;
}
break;
case 4: /*判断左倾斜数值是否与自己相同*/
while ((m4<=5)&&(flag4==0))
{
if(b[j-m4][i-m4]/2==1)
{
m4=m4+1;
t4=t4+1;
printf("t4=%d \n",t4);
}
else flag4=1;
}
while ((n4<=5)&&(flak4==0))
{
if(b[j+n4][i+n4]/2==1)
{
n4=n4+1;
s4=s4+1;
printf(" s4=%d \n",s4);
}
else flak4=1;
}
z4=s4+t4+1;
if(z4>=5)
{
p=V;
e=10;
}
break;
} /*switch*/
} /*for s*/
}
for(m=0; m<NUM1+1; m=m+1)
{
printf("\n");
for(n=0; n<NUM2+1; n=n+1)
printf("%d ",c[m][n]);
}
printf("\n");
if(p>=NUM1*NUM2+1) break;
}
for(m=0;m<NUM1+1;m=m+1)
{
printf("\n");
for(n=0; n<NUM2+1; n=n+1)
printf("%d ",c[m][n]);
printf("\n");
}
printf("p=%d\n",p);
if(p==W) printf("The winner is A!\n");
if(p==V) printf("The winner is B!\n");
if(p==NUM1*NUM2+1) printf("Noone win!");
/*输出游戏结果*/
getchar();
getchar();
}
