求助：该程序是a数组与b数组比较，如有相同四码的就把b数组的数码全部赋于a数组并输出，如没有相同四码的就输出a数组。下边的程序有两组数输出的不对：
既2 4 6 11 18 应输出是：2 4 6 11 12 却输出了：2 4 5 11 12
  1 3 6 11 18 应输出是：1 3 6 9 18 和 1 3 6 11 12 却只输出了：1 3 6 9 18
请拜托解答。多谢啦！！！

#include<stdio.h>
void main() 
{           
int i,j,s,AA,OKKO;
int a[14][5]={
                {3,5,6,11,18},
                {2,5,6,11,18},
                {1,5,6,11,18},
                {2,4,6,11,18},
                {1,3,6,11,18},
                {4,6,8,10,18},
                {2,4,7,10,18},
                {3,4,5,10,18},
        {2,4,5,10,18},
                {1,4,5,10,18},
                {2,3,5,10,18},
                {1,2,5,10,18},
                {3,5,7,9,18},
                {1,3,6,9,18},
};

 int b[14][5]={
                {1,3,6,9,18},
                {6,7,9,11,12},
                {4,7,9,11,12},
                {2,7,9,11,12},
                {1,7,9,11,12},
                {3,7,8,11,12},
        {2,5,8,11,12},
                {1,5,8,11,12},
                {2,4,6,11,12},
                {1,3,6,11,12},
                {2,4,5,11,12},
                {3,6,8,10,12},
        {3,6,8,10,11},
                {3,6,8,9,13},
                };
   for(i=0;i<14;i++)                    
    {
        for(s=0;s<14;s++)
        {
              AA=0;
            for(j=0;j<5;j++)
            {                        
            if(b[s][j]==a[i][j])//a数组和b数组对比
                AA++;           //有相同的就记数
                if(AA>=4)
                {
                   for(j=0;j<5;j++)
                    a[i][j]=b[s][j];//数组中有等于大于四个数码的将b数组的码全部赋予a数组  
                }    
            }
        }
          
      {
          for(j=0;j<5;j++)
              printf("%4d",a[i][j]);
            printf("\n");
            OKKO++;
        }
        }
   }

我说你的程序中没有限制一次比较完后就不向下比较了！所以当 2 4 6 11 18 第一次和b数组中的所有数码比较以后会先变成 2 4 6 11 12 。然后在向下和b数组中的以后的数码再继续比较！当遇到 2 4 5 11 12 时， 2 4 6 11 12  中又有四个数和 2 4 5 11 12 中的相同！所以就又变成2 4 5 11 12 了！后面的和也是这个道理！

不是很懂！

#include<stdio.h>
void main()
{           
int i,j,s,AA,OKKO;
int a[14][5]={
                {3,5,6,11,18},
                {2,5,6,11,18},
                {1,5,6,11,18},
                {2,4,6,11,18},
                {1,3,6,11,18},
                {4,6,8,10,18},
                {2,4,7,10,18},
                {3,4,5,10,18},
                {2,4,5,10,18},
                {1,4,5,10,18},
                {2,3,5,10,18},
                {1,2,5,10,18},
                {3,5,7,9,18},
                {1,3,6,9,18},
};
int b[14][5]={
                {1,3,6,9,18},
                {6,7,9,11,12},
                {4,7,9,11,12},
                {2,7,9,11,12},
                {1,7,9,11,12},
                {3,7,8,11,12},
                {2,5,8,11,12},
                {1,5,8,11,12},
                {2,4,6,11,12},
                {1,3,6,11,12},
                {2,4,5,11,12},
                {3,6,8,10,12},
                {3,6,8,10,11},
                {3,6,8,9,13},
                };
   for(i=0;i<14;i++)                    
    {
        for(s=0;s<14;s++)
        {
              AA=0;
            for(j=0;j<5;j++)
            {                        
            if(b[s][j]==a[i][j])//a数组和b数组对比
                AA++;           //有相同的就记数
                if(AA>=4)
                {
                   for(j=0;j<5;j++)
                    a[i][j]=b[s][j];//数组中有等于大于四个数码的将b数组的码全部赋予a数组
                   goto loop;
                }  
            }
        }
loop:
        {
          for(j=0;j<5;j++)
              printf("%4d",a[i][j]);
            printf("\n");
            OKKO++;
        }
   }
}

[[it] 本帖最后由 醉心无恨 于 2009-7-26 00:26 编辑 [/it]]

现在咋样啊？差不多啦吧！

你把我第一个问题给解决啦。但第二个问题该如何修改程序？多谢！！！
第二个问题：1 3 6 11 18 应输出是：1 3 6 9 18 和 1 3 6 11 12 却只输出了：1 3 6 9 18
（意思是：当a数组在对比b数组过程中，a数组不要发现有相同四码的就退出，要继续向下对比b数组的其他数组并再一次次的替换至到对比完b数组。多谢！！！)