我是新手，这是我昨晚编的程序，编译环境是MS_VC++6.0,请大家多多指教啊:

#include<iostream>
#include<string>
using namespace std;

int n[5];

//检测数字
int check(int a)
{
if(a>=100000)
{
cout<<"\n输入的数字不能超过5个！没看见吗？\n\n";
return 0;
}
else return 1;
}

//提取数字
int get(int num)
{
int i;

for(i=0;i<5;i++)
{
n[i]=num%10;
num=(num-n[i])/10;
}

return n[i];
}

//转换成汉字
string convert(int a)
{
string c1[10];
switch (a)
{
case 0:
c1[0]="零";
break;
case 1:
c1[1]="一";
break;
case 2:
c1[2]="二";
break;
case 3:
c1[3]="三";
break;
case 4:
c1[4]="四";
break;
case 5:
c1[5]="五";
break;
case 6:
c1[6]="六";
break;
case 7:
c1[7]="七";
break;
case 8:
c1[8]="八";
break;
case 9:
c1[9]="九";
break;
}

return c1[a];
}

//显示单位

string danwei(int a)
{
string c2[5];
switch(a)
{
case 0:
c2[0]="";
break;
case 1:
c2[1]="十";
break;
case 2:
c2[2]="百";
break;
case 3:
c2[3]="千";
break;
case 4:
c2[4]="万";
break;
}
return c2[a];
}

//打印结果
void print()
{
int i,flag1=-1,flag2=-1;

for(i=0;i<5;i++)
if(n[i]!=0) flag1=i;
for(i=4;i>=0;i--)
if(n[i]!=0) flag2=i;

if(flag1!=-1&&flag2!=-1)
{
cout<<"\n转换为汉字为：";
for(i=flag1;i>=flag2;i--)
{
if(n[i]!=0) cout<<convert(n[i])<<danwei(i);
else
if(n[i+1]!=0)
cout<<convert(n[i]);
}
cout<<endl<<endl;
}
else
cout<<"\n转换为汉字为：零\n\n";
}

int main()
{
cout<<"请输入阿拉伯数字（不超过5个）：";
int num;
cin>>num;

if(check(num))
{
get(num);
print();
}

return 0;
}

不用写这么长吧？我也写了一个，还有点缺陷，不过基本可用了
[CODE]#include <iostream>
using namespace std;
char * converion(unsigned _int64 ulData)
{
char sz[128];
static char szResult[128];
unsigned int i, count = 0, ulLength = 0;
static char *szByte[]= {"零", "一","二","三","四","五","六","七","八","九"};
static char *szDigit[] = {NULL, "十", "百", "千", "万", "十", "百", "千", "亿"};
static unsigned int ulByteLen = sizeof(szByte) / sizeof(char*);
static unsigned int ulDigitLen = sizeof(szDigit) / sizeof(char*);

memset(szResult, 0, sizeof(szResult));
_ui64toa(ulData, sz, 10);
ulLength = strlen(sz);
for (i = 0; i < ulLength; i ++)
{
count = sz[i] - 48;
if (0 == count)
{
count = ( ulLength - i - 1) % (ulDigitLen - 1);
if (count == 4 || count == 8)
strcat(szResult, szDigit[count]);
continue;
}
strcat(szResult, szByte[count]);
count = ( ulLength - i - 1) % (ulDigitLen - 1);
if (0 == count)
{
count = (( ulLength - i - 1) / (ulDigitLen - 1) > 0) ? 8 : 0;
}
if (szDigit[count])
{
strcat(szResult, szDigit[count]);
}
}
return szResult;
}
int main(void)
{
unsigned _int64 ulInput;
char * sz;
ulInput = 5764607523134234879;
sz = converion(ulInput);
cout<<sz<<endl;

return 0;
}[/CODE]

[此贴子已经被作者于2006-10-12 18:07:04编辑过]

楼上的程序，如果把输入的数字改为：4205（四千二百零五），输出则是：四千二百五（4250），把零忽略了。

楼上的朋友说对了，昨天正好下班了，没来得及改，刚修改了一下，应该没什么错误了

[CODE]char * converion(unsigned _int64 ulData)
{
char sz[128];
static char szResult[128];
unsigned int i, count = 0, ulLength = 0, ulPre = 0xFFFFFFFF;
static char *szByte[]= {"零", "一","二","三","四","五","六","七","八","九"};
static char *szDigit[] = {NULL, "十", "百", "千", "万", "十", "百", "千", "亿"};
static unsigned int ulByteLen = sizeof(szByte) / sizeof(char*);
static unsigned int ulDigitLen = sizeof(szDigit) / sizeof(char*);

memset(szResult, 0, sizeof(szResult));
_ui64toa(ulData, sz, 10);
ulLength = strlen(sz);
for (i = 0; i < ulLength; i ++)
{
count = sz[i] - 48;
if (0 == count)
{
count = ( ulLength - i - 1) % (ulDigitLen - 1);
if (count == 4 || count == 8)
{
strcat(szResult, szDigit[count]);
ulPre = 1;
}
else
{
ulPre = 0;
}
continue;
}
if ( ulPre == 0 )
{
strcat(szResult, szByte[0]);
}
ulPre = count;
strcat(szResult, szByte[count]);
count = ( ulLength - i - 1) % (ulDigitLen - 1);
if (0 == count)
{
count = (( ulLength - i - 1) / (ulDigitLen - 1) > 0) ? 8 : 0;
}
if (szDigit[count])
{
strcat(szResult, szDigit[count]);
}
}
return szResult;
}[/CODE]

呵呵，这个程序有意思阿。