回复 8楼 canxden
不简单
程序代码:float a1,a2,answer;
char op;
scanf("%f%c%f",&a1,&op,&a2);
if(op=='+'||op=='-'||op=='*'||op=='/')
{switch(op) {
case '+':answer=a1+a2;break;
case '-':answer=a1-a2;break;
case '*':answer=a1*a2;break;
case '/':answer=a1/a2;break;
}
printf("Answer is %f\n",answer);}
else printf("输入错误");