for(j=1;j<=n;j++) { for(k=j;k<=n-1;k++) if(b[j]<b[k+1]){t=b[j]; b[j]=b[k+1];b[k+1]=t;a[j]=k+1; printf("第%d名%d号%.2f",j,a[j],b[j]); } }[local]1[/local]