FileOpen函数打开的问题

yymsyc 发布于 2006-10-16 16:27， 1296 次点击

string str_filename = "test.txt"
int i_fileno = FileOpen(str_filename,LineMode!,Write!,LockWrite!,Append!)
这样为什么报错？

int i_fileno = FileOpen("test.txt",LineMode!,Write!,LockWrite!,Append!)
这样为什么就可以

谢谢高手指点

1 回复

潇洒老乌龟2006-10-17 09:30

string str_filename = "test.txt"
integer i_fileno
i_fileno = FileOpen(str_filename,LineMode!,Write!,LockWrite!,Append!)