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#2
dongmatlab2006-06-26 20:59
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f='(0.1576-(0.1501*x(1)+0.8499*x(2)))^2+(0.1184-(0.1576*x(1)+0.8424*x(2)))^2+(0.1443-(0.1184*x(1)+0.8816*x(2)))^2+(0.8424-(0.1501*x(3)+0.8499*x(4)))^2+(0.8816-(0.1576*x(3)+0.8424*x(4)))^2+(0.8557-(0.1184*x(3)+0.8816*x(4)))^2';
其中x(1)+x(3)=1;x(2)+x(4)=1
谢谢大家了,教教我啊,我晚上在线等。谢谢