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#2
liu_mack2006-05-01 16:55
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如何动态打开用已知的窗口:
如：string ls_winname ,ls_id
select ls_winname into :ls_winname from sys where id = :ls_id
现在要打开ls_winname 变量所获得的名称的WINDOW，请问如何写代码？？
谢谢各位大侠！