|
#2
diycai2021-11-11 12:49
 程序代码：#include <conio.h> void main() { int map[] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}; char prev, cur, next; prev = 0; while (1) { cur = getchar(); if (cur == '-') { next = getchar(); if (map[prev] && map[next] && ((prev^next)<' ') && prev+1<next) { while (prev+1 < next) { prev++; printf("%c", prev); } } else { printf("%c", cur); } cur = next; } printf("%c", cur); if (cur == '\n') { break; } prev = cur; } } |
在保存字符串时，对出现在连续位置的若干个字符，如这些字符在ASCII表中也是连续出现，则可以将这些字符使用缩写形式进行保存，以节省保存空间。例如用A-Z表示ABCDEFGHIJKLMNOPQRSTUVWXYZ，1-5表示12345，c-f表示cdef。
【要求】用指针完成
输入：包含缩写形式的字符串
输出：将缩写形式进行还原后的字符串
说明：只处理大小写字母和数字，即对于形如A-9，a-C这样的缩写不进行处理
测试用例1
输入：0-9
输出：0123456789
测试用例2
输入：a-z
输出：abcdefghijklmnopqrstuvwxyz
测试用例3
输入：G-I
输出：GHI
测试用例4
输入：ABDG-K035-9abd-h
输出：ABDGHIJK0356789abdefgh