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#2
diycai2021-11-11 12:36
1-2 a-b 紧邻数不处理
1-3-5 解释为12345  程序代码：#include <conio.h> void main() { int map[] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}; char prev, cur, next; prev = 0; while (1) { cur = getchar(); if (cur == '-') { next = getchar(); if (map[prev] && map[next] && ((prev^next)<' ') && prev+1<next) { while (prev+1 < next) { prev++; printf("%c", prev); } } else { printf("%c", cur); } cur = next; } printf("%c", cur); if (cur == '\n') { break; } prev = cur; } } |
#include <stdio.h>
#include <stdlib.h>
/*在保存字符串时，对出现在连续位置的若干个字符，
如这些字符在ASCII表中也是连续出现，则可以将这些字符使用缩写形式进行保存，以节省保存空间。
例如用A-Z表示ABCD...XYZ，1-5表示12345，c-f表示cdef。
输入：包含缩写形式的字符串
输出：将缩写形式进行还原后的字符串
说明：只处理大小写字母和数字，即对于形如A-9，a-C这样的缩写不进行处理
*/
int main(int argc, char *argv[]) {
static char a[1000],b[1000];
int i,j;
gets(a);
for(i=0,j=0;a[i]!='\0';i++,j++){
if(a[i]==45){
if(((a[i-1]>=48&&a[i-1]<=57&&a[i+1]>=48&&a[i+1]<=57)||(a[i-1]>=65&&a[i-1]<=90&&a[i+1]>=65&&a[i+1]<=90)||(a[i-1]>=97&&a[i-1]<=122&&a[i+1]>=97&&a[i+1]<=122))&&(a[i-1]<a[i+1])){
while(b[j-1]!=a[i+1]-1){
b[j]=b[j-1]+1;
j++;
}
i++;
}
}
b[j]=a[i];
}
puts(b);
return 0;
}
已经指针形式编写，小弟不知道咋弄了。希望大神给与帮助