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#2
rjsp2021-05-31 17:06
你只能返回数组的地址（或首元素的地址），不能返回一个数组。
因为C/C++中不允许数组复制，免得不小心影响性能。 另外，换个正儿八经的编译器，免得错误的语法也能编译通过  程序代码：#include <stdio.h> const char** names( size_t* psize ) { static const char* a[] = { "Jan","Feb","Mar","Apr","May","Jun","Juy" }; *psize = sizeof(a) / sizeof(a[0]); return a; } int main( void ) { size_t size; const char** p = names( &size ); for( size_t i=0; i!=size; ++i ) puts( p[i] ); } |
NO.1
程序代码：#include <stdio.h>
char** name(int *pn)
{
static char* a[] =
{
"Jan","Feb","Mar","Apr","May","Jun","Juy"
};
*pn = sizeof(a) / sizeof(a[0]);
return a;
}
void main()
{
int pn;
char** p;
p = name(&pn);
while(pn-->0)
printf("%s\n",*p++ );
}
char** name(int *pn)
{
static char* a[] =
{
"Jan","Feb","Mar","Apr","May","Jun","Juy"
};
*pn = sizeof(a) / sizeof(a[0]);
return a;
}
void main()
{
int pn;
char** p;
p = name(&pn);
while(pn-->0)
printf("%s\n",*p++ );
}
No.2
程序代码：#include <stdio.h>
char(*name(int* pn))[]
{
static char* a[] =
{
"Jan","Feb","Mar","Apr","May","Jun","Juy"
};
*pn = sizeof(a) / sizeof(a[0]);
return a;
}
void main()
{
int pn;
char (*p)[];
p = name(&pn);
while (pn-- > 0)
printf("%s\n", *p++);
}
char(*name(int* pn))[]
{
static char* a[] =
{
"Jan","Feb","Mar","Apr","May","Jun","Juy"
};
*pn = sizeof(a) / sizeof(a[0]);
return a;
}
void main()
{
int pn;
char (*p)[];
p = name(&pn);
while (pn-- > 0)
printf("%s\n", *p++);
}