求各位大佬解释一下段错误，我程序里有个段错误但是找不到啊。 - 编程论坛

#2

forever742020-05-16 18:55

段错误不是编译错误，是运行错误。
你运行截图啊。

#3

forever742020-05-16 18:58

另外，两个循环搭配不对，这样是冒不起泡的。
起码得让内循环和外循环相关才有意义吧。

[此贴子已经被作者于2020-5-16 19:00编辑过]

#4

魂之子2020-05-17 11:06

回复 3楼 forever74

https://
就是这题大佬，能帮看一眼吗？

#5

rjsp2020-05-17 12:04

程序代码：

#include <stdio.h>
#include <stdlib.h>

/*
void bubblesort( unsigned arr[], size_t n )
{
    for( size_t i=0; i<n-1; ++i )
    {
        for( size_t j=1; j<n-i; ++j )
        {
            if( arr[j] < arr[j-1] )
            {
                unsigned tmp = arr[j];
                arr[j] = arr[j-1];
                arr[j-1] = tmp;
            }
        }
    }
}
*/
int unsigned_cmp( const void* pa, const void* pb )
{
    unsigned a = *(unsigned*)pa;
    unsigned b = *(unsigned*)pb;
    if( a < b ) return -1;
    if( a > b ) return +1;
    return 0;
}

unsigned sum( const unsigned arr[], size_t n )
{
    unsigned result = 0;
    for( size_t i=0; i!=n; ++i)
        result += arr[i];
    return result;
}

int main( void )
{
    unsigned n;
    scanf( "%u", &n );

    unsigned a[100000];
    for( size_t i=0; i!=n; ++i)
        scanf( "%u", &a[i] );

    // bubblesort( a, n);
    qsort( a, n, sizeof(*a), &unsigned_cmp );

    unsigned sum1 = sum( a, n/2 );
    unsigned sum2 = sum( &a[n/2], n-n/2 );
    unsigned fsum = sum2-sum1;
    printf("Outgoing #: %u\nIntroverted #: %u\nDiff = %u\n", n-n/2, n/2, fsum );
}