含有指针的函数调用错误

#include <stdio.h>
int max(int a[], int n, int *p); //声明max函数的找最大值和下标的
int min(int a[], int n, int *p); //声明min函数的找最大值和下标的
int main()
{
    int a[10] = {3, 8, 6, 9, 1, 2, 3, 5, 4, 7};
    int max, min;
    max(a, 10, &max);              //错误
    min(a, 10, &min);                //错误

    return 0;
}
int max(int a[], int n, int *p)
{
    int index, count;
    *p = a[0];
    for (n = 0; n < 10; n++)
    {
        if (a[n] > *p)
        {
            *p = a[n];
            index = n;
        }
        else if (max == a[n])
        {
            count++;
        }
    }
}
int min(int a[], int n, int *p)
{
    int index, count;
    *p = a[0];
    for (n = 0; n < 10; n++)
    {
        if (a[n] < *p)
        {
            *p = a[n];
            index = n;
        }
        else if (min == a[n])
        {
            count++;
        }
    }
}