编程新手求解

问题：从键盘输入一指定金额（以元为单位，如345.78），然后显示支付该金额的各种面额人民币数量（在人民币总数量最少的情况下，显示100元、50元、10元、5元、2元、1元、1角、5分、1分各多少张）。
这道题我在百度上搜到了答案，不过我想自己用if语句写出来，但不知道为什么出错了，求助各位大佬。
代码如下：
#include<stdio.h>
int main()
{
    double x;
    int a, b, c, d, e, f, g, h, i;
    printf("请输入金额:");
    scanf_s("%lf", &x);
    if (x / 100 != 0)
    {
        a = x / 100;
        if ((x - a * 100) > 50)
        {
            b = 1;
            c = (x - a * 100 - 50) / 10;
        }
        else
        {
            b = 0;
            c = (x - a * 100) / 10;
        }
        if ((x - a * 100 - b * 50 - c * 10) >= 5)
        {
            d = 1;
            if ((x - a * 100 - b * 50 - c * 10 - 5) == 4)
                e = 2;
            else
                if ((x - a * 100 - b * 50 - c * 10 - 5) >= 2)
                    e = 1;
                else
                    e = 0;
        }
        else
        {
            d = 0;
            if ((x - a * 100 - b * 50 - c * 10) == 4)
                e = 2;
            else
                if ((x - a * 100 - b * 50 - c * 10) >= 2)
                    e = 1;
                else
                    e = 0;
        }
        if ((x - a * 100 - b * 50 - c * 10 - d * 5 - e * 2) == 1)
            f = 1;
        else
            f = 0;
        g = (x - a * 100 - b * 50 - c * 10 - d * 5 - e * 2 - f) / 0.1;
        if ((x - a * 100 - b * 50 - c * 10 - d * 5 - e * 2 - f - g * 0.1) >= 0.05)
        {
            h = 1;
            i = (x - a * 100 - b * 50 - c * 10 - d * 5 - e * 2 - f - g * 0.1 - h * 0.05) /0.01;
        }
        else
        {
            h = 0;
            i = (x - a * 100 - b * 50 - c * 10 - d * 5 - e * 2 - f - g * 0.1) / 0.01;
        }
    }
    else
        printf("error");
    printf("%2d%2d%2d%2d%2d%2d%2d%2d%2d", a, b, c, d, e, f, g, h, i);
    return 0;
}

最后一个数字答案是3