一道关于鸡和兔的算法题

public static int jishu(){
        int [] array = {0,1,2,3,4,5};
        int jijiao=0,tujiao;
        for(int i=0 ;i<array.length;i++){
            if(array[i] == 0) continue;
            for(int j=0 ;j<array.length;j++){
                if(i == j) continue;
                for(int k=0 ;k<array.length;k++){
                    if(i == k || j==k) continue;
                     jijiao = i*100+j*10+k;
                     tujiao = jijiao *2;
                     if(jijiao%2 == 0 && jijiao/2 == tujiao/4 ){
                         System.out.println("鸡兔各"+jijiao/2+"只，鸡脚"+jijiao+"兔脚"+tujiao);
                         return jijiao;
                     }
                }
            }
        }
        return jijiao;
    }

    public static void main(String[] args) {
        jishu();
    }

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