字符串中计算各类字符个数

#include<stdio.h>
main()
{
    char c;
    scanf("%s",c);
    int letter=0,space=0,number=0,other=0;
    while((c=getchar())!='\n')
    {
        if((c>='a'&&c<='z')||(c>='A'&&c<='Z'))
        {
            letter++;
        }
        else if(c==' ')
        {
            space++;
        }
        else if(c>='0'&&c<='9')
        {
            number++;
        }
        else
        {
            other++;
        }
    }
    other=other-1;
    printf("letter:%d\nspace:%d\nnumber:%d\nother:%d\n",letter,space,number,other);
}
输入：   123!/#fff@       //*要求以@结束且@不计入数目，但是我不会弄*
结果：letter:3
      space:0
      number:3
      other:3
空格应该是三个，咋回事呢?