注册 登录
编程论坛 C语言论坛

keil说switch.c(6): error C141: syntax error near 'void'谁能看看什么问题啊啊啊啊啊啊啊

silencejjj 发布于 2019-10-25 14:52, 3682 次点击
#include<reg51.h>
#include<intrins.h>
#define uchar unsigned char
#define uint  unsigned int
uchar code seg[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90} //&sup1;&sup2;&Ntilde;&ocirc;LED&Ecirc;&yacute;&Acirc;&euml;&sup1;&Uuml;&para;&Icirc;&Acirc;&euml;±í
void delay (uint t)      //&Ntilde;&Oacute;&Ecirc;±&ordm;&macr;&Ecirc;&yacute;
{
    uchar j;
 while(t -- )
 for(j=0;j<200;j++);
}
void main()   //&Ouml;÷&ordm;&macr;&Ecirc;&yacute;
{
    do
{
char state;
p1=0xff;//p1&Icirc;&ordf;&Ecirc;&auml;&Egrave;&euml;&iquest;&Uacute;
state=p1;//&para;&Aacute;p1&micro;&Auml;×&acute;&Igrave;&not;&Euml;&Iacute;&Egrave;&euml;state
state=state&0x03;//&AElig;&Aacute;±&Icirc;P1&iquest;&Uacute;&cedil;&szlig;6&Icirc;&raquo;&micro;&Auml;×&acute;&Igrave;&not;
switch(state)//&Aring;&ETH;&para;&Iuml;p1&iquest;&Uacute;&micro;&Iacute;&Aacute;&frac12;&Icirc;&raquo;&micro;&Auml;×&acute;&Igrave;&not;
{
    case 0:keep();break;
    case 1:plus();break;
    case 2:minus();break;
    case 3:keep();break;
}
}
while(1);
}
void plus(void)//&Otilde;&yacute;&Iuml;ò&Ntilde;&shy;&raquo;·&ordm;&macr;&Ecirc;&yacute;
{
    uchar i;
    while(1)
{
    for(i=0;i<9;i++)
    {
    P0=seg[i];
    delay(900);
    }   
}
}
void minus(void)//·&acute;&Iuml;ò&Ntilde;&shy;&raquo;·&ordm;&macr;&Ecirc;&yacute;
{
    uchar i;
    while(1)
{
    for(i=9;i>0;i--)
    {
    P3=seg[i];
    delay(900);
    }   
}
3 回复
#2
纯蓝之刃2019-10-25 15:00
uchar code seg[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90}最后没加;号
#3
silencejjj2019-10-25 15:02
回复 2楼 纯蓝之刃
哇,我真的感谢死您了!
#4
自学的数学2019-10-25 16:27
基本的标点符号都不会处理,真不敢想象啊。
1