注册 登录
编程论坛 C++教室

deque进行pop_back()出错

陈紫文 发布于 2018-10-07 16:19, 2813 次点击
我进行pop_back操作时,出现运行时错误,我晓不得咋个改,但晓得是pop_back出问题,帮我看一下



#include <iostream>
#include <deque>
#include <algorithm>
#include <iterator>
#include <time.h>
using namespace std;
enum{SIZE=20};
int main()
{
    srand(time(0));
    int arr[SIZE];
    for (int i = 0; i < SIZE;i++)
    {
        arr[i] = rand()%100;
    }
    deque<int>pm;
    pm.insert(pm.begin(), arr, arr + SIZE);
    for (deque<int>::iterator p = pm.begin(); p != pm.end();p++)
    {
        cout << "pm:" << *p << endl;
        
    }
    /*
    pm.push_back(1);
    pm.push_back(1);
    pm.push_back(1);
    pm.push_back(1);
    pm.push_back(1);
    pm.push_back(1);
    */
    sort(pm.begin(), pm.end());
   
    for (int i = 0; i < SIZE;i++)
    {
        cout << "pm["<<i<<"]:" << pm[i] << endl;
    }
    //pm.pop_back();
    pm.pop_back();
    for (int i = 0; i < SIZE; i++)
    {
        cout << "pm[" << i << "]:" << pm[i] << endl;
    }
    while (1);
    return 0;
}
3 回复
#2
Jonny02012018-10-07 19:01
跟 pop_back 没关系
你 pop 了之后是不是应该让循环的次数也 -1?
#3
yangfrancis2018-10-07 19:55
改成这种循环条件
for (deque<int>::iterator p = pm.begin(); p != pm.end();p++)
不然你的SIZE在数组元素增删之后就不能用了
#4
陈紫文2018-10-12 19:02
谢谢你们了
1