简单的小程序 - 编程论坛

卢飞2018-07-11 18:45

import *;
import java.util.*;

public class B {

public int lj(int a,int number) {

          if(number==1 && number >0)
          {
                return a;
          }else{

                return lj(a,number-1)+a*bs(number-1);
          }

}
  public int bs(int number)
  {
         if(number==1)
          {
                return 10;
          }else{

                 return 10*bs(number-1);
       }
  }




public static void main(String[] args)
{
     int sum=0;
     B b = new B();
          InputStream in = System.in;
    Scanner scanner = new Scanner(in);
     System.out.println("输入个数");
     int number =scanner.nextInt()+1;
       System.out.println("输入数值");
     int a =scanner.nextInt();
    for(int i=1;i<number;i++){
          sum=sum+b.lj(a,i);
     }

     System.out.println(sum);
      System.out.println("=====");
}
}

疯狂的小a2018-07-11 22:59

程序代码：

import java.util.Scanner;

/*题目：求s=a+aa+aaa+aaaa+aa...a 的值,其中a 是一个数字。例如2+22+222+2222+22222(此
时共有5 个数相加),几个数相加有键盘控制。*/

@SuppressWarnings("all")
public class Test {
    public static void main(String[] args) {
        for(;;){
            System.out.println("请输入一个数1-9:");
            int num = new Scanner(System.in).nextInt();
            if(num<=0||num>=10){
                System.out.println("你的输入不合法!");
                continue;
            }
            System.out.println("请确定多少个数字相加:");
            int times = new Scanner(System.in).nextInt();
            int sum = 0;
            String str="";
            String str2="";
            for(int i=1;i<=times;i++){
                str = str+num;
                if(i!=times){
                    str2 = str2+str+"+";
                }else{
                    str2 = str2+str;
                }
                sum+=Integer.parseInt(str);
            }
            System.out.println(str2+" = "+sum);
        }

    }
}