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#2
ehszt2018-03-24 15:48
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下面是我自己打的源代码，但是运行的时候出现了一点问题，如图：
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程序运行的时候为什么会多出来两个0？是不是和return有关系？不太懂return，希望能帮助我解决一下，谢谢！
程序代码：#include<iostream>
using namespace std;
int zhengxing(int,int);
double fudian(double,double);
int main()
{
cout<<zhengxing(21,33);
cout<<fudian(123.456,666.666);
return 0;
}
int zhengxing(int a,int b)
{
cout<<"整型变量交换前a="<<a<<"\tb="<<b<<endl;
a=a^b;
b=a^b;
a=a^b;
cout<<"整型变量交换后a="<<a<<"\tb="<<b<<endl;
return 0;
}
double fudian(double a,double b)
{
cout<<"浮点型变量交换前a="<<a<<"\tb="<<b<<endl;
int*ap,*bp;
ap=(int*)(&a);
bp=(int*)(&b);
*ap=(*ap)^*(bp);
*bp=(*ap)^*(bp);
*ap=(*ap)^*(bp);
ap++;
bp++;
*ap=(*ap)^*(bp);
*bp=(*ap)^*(bp);
*ap=(*ap)^*(bp);
cout<<"浮点型变量交换后a="<<a<<"\tb="<<b<<endl;
return 0;
}
using namespace std;
int zhengxing(int,int);
double fudian(double,double);
int main()
{
cout<<zhengxing(21,33);
cout<<fudian(123.456,666.666);
return 0;
}
int zhengxing(int a,int b)
{
cout<<"整型变量交换前a="<<a<<"\tb="<<b<<endl;
a=a^b;
b=a^b;
a=a^b;
cout<<"整型变量交换后a="<<a<<"\tb="<<b<<endl;
return 0;
}
double fudian(double a,double b)
{
cout<<"浮点型变量交换前a="<<a<<"\tb="<<b<<endl;
int*ap,*bp;
ap=(int*)(&a);
bp=(int*)(&b);
*ap=(*ap)^*(bp);
*bp=(*ap)^*(bp);
*ap=(*ap)^*(bp);
ap++;
bp++;
*ap=(*ap)^*(bp);
*bp=(*ap)^*(bp);
*ap=(*ap)^*(bp);
cout<<"浮点型变量交换后a="<<a<<"\tb="<<b<<endl;
return 0;
}
