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函数指针为什么传递不过去~格式有错误吗?高手进来解答下!谢谢..

新人学习 发布于 2017-12-28 12:53, 1048 次点击
#include<iostream>

using namespace std;

double add(double, double);

double aadd(double, double, double *ad(double, double));

int main()
{
    double h;
    h=aadd(3,5,add);
    cout << "h = "<< h << endl;
    system("pause");
    return 0;
}



double aadd(double a, double b, double *ad(double, double))
{
    double m = *ad(a, b);
    return m;
}


double add(double x, double y)
{
    return x + y;
}
2 回复
#2
rjsp2017-12-28 14:48
编译失败就应该贴出编译器给出的编译错误信息!
比如 aadd(3,5,add); 报错:cannot convert parameter 3 from 'double (__cdecl *)(double,double)' to 'double *(__cdecl *)(double,double)'

否则不知道错误所在的话,别人怎么改?
程序代码:
#include <iostream>
using namespace std;

double add(double, double);
double aadd(double, double, double (*ad)(double, double));

int main( void )
{
    double h = aadd(3,5,add);
    cout << "h = "<< h << endl;

    return 0;
}

double aadd(double a, double b, double (*ad)(double, double))
{
    double m = (*ad)(a, b);
    return m;
}

double add(double x, double y)
{
    return x + y;
}

#3
新人学习2017-12-28 16:50
谢谢,以后会注意的...
1