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#2
yangfrancis2017-06-10 10:05
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#include<stdio.h>
#include<math.h>
#include<Windows.h>
#include<cstdio>
using namespace std;
int main()
{
float a, b, c, dell;
printf("依次输入二元一次方程的三个系数,以空格隔开\n");
scanf("%f%f%f", &a, &b, &c);
dell = b*b - 4 * a*c;
if (dell >=0)
{
float x_1, x_2;
float e = sqrt(dell);
x_1 = (-b + e) / (2*a);
x_2 = (-b - e) / (2*a);
printf("方程的解为:X1= %f \nX2= %f\n", &x_1, &x_2);
}
else
printf("方程无解\n");
system("pause");
}