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比较字符串,数组形式

稻草人25 发布于 2017-03-27 19:37, 1519 次点击
从命令行传入一个包含十个字符的字符串,把该字符串与程序中给定的字符串"bacdbcabca"依次比较,统计两个串中对应字符相等的数目。然后输出命令行输入的字符串,并把两个串中对应字符不相等的字符替换为'@'后生成的新串输出,最后输出两个串中相等字符的数目
package ch3;
import java.util.Scanner;
public class compare {
        String a[] = new String[10];
        public static void main(String[] args) {
            int t = 0;
            String[] b = new String[]{"bacdbcabca"};
            for (String n : b)
                System.out.print(n + " ");
            System.out.println();
            Scanner stdin = new Scanner(System.in);
            String a[] = new String[10];
            for (int i = 0; i < 10; i++) {
                a[i] = stdin.next();
                if (!(a[i].equals(b[i]))) {
                    t++;
                    a[i] = "@";
                }
            }
            System.out.println(t);
            for (String n : a)
                System.out.print(n);
        }
    }
运行不起来,求找错
1 回复
#2
纵横阳仔2017-03-27 20:53
应该是字符串,不是字符串数组
1