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求VB挂轮比代码

hl2388817942 发布于 2016-01-17 12:52, 1498 次点击
(51/55)*(83/88)=.874586776859504

Dim a As Long, b As Long, c As Long, d As Long
Dim m As Double, n As Double
Dim k As Double

Dim a1 As Long, b1 As Long, c1 As Long, d1 As Long
Dim m1 As Double


k = 1
For a = 30 To 100
For b = 30 To 100
For c = 30 To 100
For d = 30 To 100
m = (a / b) * (c / d)
n = Abs(m - 0.8745865231)
If n < k Then
    k = n
    a1 = a
    b1 = b
    c1 = c
    d1 = d
    m1 = m
End If
Next d
Next c
Next b
Next a

Print "("; a1; "/"; b1; ")*("; c1; "/"; d1; ")="; m1
Debug.Print "(" & a1 & "/" & b1 & ")*(" & c1 & "/" & d1 & ")=" & m1


这个代码,我是在窗体有个text1.text,然后在text。text中输入实数,一般是小数点后七位,然后然后输出挂轮比,要求误差小于0.0002.这个程序不运行,大侠,看看应该怎么写,谢谢!
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