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下面程序有两个错误,但刚学java,不太了解有参和无参构造方法,哪位大神能帮忙指点一下

暗静暗静呢 发布于 2015-09-26 00:50, 652 次点击
class Student{
     private String name;
     private int grade;
 
  public String getName(){
      return name;
  }
  public void setName(String name1){
      name=name1;
  }
  public int getGrade(){
      return grade;
  }
  public void setGrade(int grade1){
      if(grade1<0){
         System.out.println("成绩错误");
      }else{
          grade=grade1;
      }
   }
  public Student(String name,int grade){
        this.name=name;
        this.grade=grade;
  }   
public class xinxin {
    public static void main(String[] args) {
       Student stu1=new Student();
       stu1.setName("张三");
       stu1.setGrade(100);
       Student stu2=new Student("李四",59);
      
    }
}
 }
3 回复
#2
林月儿2015-09-26 07:49
程序代码:
class Student{
    private String name;
    private int grade;

    public String getName(){
        return name;
    }
    public void setName(String name){
        this.name=name;
    }
    public int getGrade(){
        return grade;
    }
    public void setGrade(int grade){
        if(grade<0){
            System.out.println("成绩错误");
        }else{
            this.grade=grade;
        }
    }
    public Student(String name,int grade){
        this.name=name;
        this.grade=grade;
    }   
    public Student(){
        
    }
}
public class xinxin {
    public static void main(String[] args) {
        Student stu1=new Student();
        stu1.setName("张三");
        stu1.setGrade(100);
        Student stu2=new Student("李四",59);
    }
}
#3
暗静暗静呢2015-09-26 11:23
回复 2楼 林月儿
Student stu2=new Student("李四",59);那一行还是显示 The value of the local variable stu2 is not used;怎么解决啊
#4
林月儿2015-09-26 12:17
以下是引用暗静暗静呢在2015-9-26 11:23:40的发言:

Student stu2=new Student("李四",59);那一行还是显示 The value of the local variable stu2 is not used;怎么解决啊


那是未使用警告
可以写成new Student("李四",59);
也可以加一句
stu2.setName("hehe");
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