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#2
rjsp2014-03-13 10:59
函数可以重载，所以语法上没有必须加入偏特化的功能
 程序代码：#include <iostream> using namespace std; template<class T1, class T2, class T3> void demo( T1 t1, T2 t2, T3 t3 ) { cout << "usual template " << endl; } template<> void demo<int,int,int>( int t1, int t2, int t3 ) { cout << "specialization template" << endl; } template<class T1, class T2> void demo( T1 t1, T2 t2, const char* t3 ) // 其实是重载 { cout << "partial specialization template" << endl; } int main() { demo( 1.1, 2.2, 3.3 ); demo( 1, 2, 3 ); demo( 1.1, 2.1, "3" ); return 0; } |
template<class T1, class T2>class Pair(T1, T2);
template<class T1>class Pair<int>(T1, int);
我有个小问题就是函数模板能否部分具体化：
template<class T1, class T2>void demo(T1 t1, T2 t2){cout<<"usual function template"<<endl;}
template<class T1>void demo<int> demo(T1 t1, int t2){cout<<"partial specialization template"<<endl;}
我在VS2010 里运行出现错误：
error C2768: “demo”: 非法使用显式模板参数
我想问问是我函数写错还是模板函数本身就无法部分具体化？
程序代码：#include<iostream>
using std::cout;
using std::endl;
template <class T1, class T2, class T3>
void demo(T1 t1,T2 t2, T3 t3){
cout<<"usual template "endl;
}
template<class T1, class T2>void demo<T1,T2,int>( T1 t2, T2 t3,int i){
cout<<"partial specialization template "<<endl;
}
template <>
void demo<int,int,int>(int t1,int t2, int t3){
cout<<" specialization template: "<<t1<<": "<<t2<<": "<<t3<<endl;
}
int main(){
demo(1.1,2.2,3.3);
demo(1.1,2.1,3);
demo(1,2,3);
getchar();
return 0;
}