计算器添加连乘连除功能 - 编程论坛

#2

yuccn2013-12-29 21:28

表示不懂你干嘛

#3

wp2319572013-12-29 21:58

1/2/3/4/5/6 ???

#4

做梦追梦2013-12-29 23:36

解决了：
void CCalculatorDlg::cal()
{
    int curi=0,flagg=0,flagg1=0;
    double nown=1,kret[15];
    for(int i=1;i<15;i++)
    {
        switch(m_Operation[i])
        {
        case 3:
            if (flagg==0)//第一次
            {
                nown=m_number[i]*m_number[i+1];
                flagg=1;
            }
            else
            {
                nown*=m_number[i+1];
            }
            break;
        case 4:
            if (flagg==0)//第一次
            {
                nown=(double)m_number[i]/m_number[i+1];
                flagg=1;
            }
            else
            {
                nown=(double)nown/m_number[i+1];
            }
            break;
        case 1:
        case 2:
            if (flagg==1)
            {
                kret[curi++]=nown;
            }
        case 999://运算结束
            if (m_Operation[i-1]==3 || m_Operation[i-1]==4)
            {//最后一个操作符是乘或除的话
                kret[curi++]=nown;
                flagg1=1;
            }
            break;
        }
        if (flagg1==1)
        {
            break;
        }
    }
    int nowq=0;
    if (m_Operation[1]==3 || m_Operation[1]==4)
    {
        m_result=kret[nowq++];
    }
    else
    {
        m_result=m_number[1];
    }
    for(i=1;i<15;i++)
        if(m_Operation[i]==1)
            if (m_Operation[i+1]==3 || m_Operation[i+1]==4)
                m_result=m_result+kret[nowq++];
            else
                m_result=m_result+m_number[i+1];
            else if (m_Operation[i]==2)
                if (m_Operation[i+1]==3 || m_Operation[i+1]==4)
                    m_result=m_result-kret[nowq++];
                else
                    m_result=m_result-m_number[i+1];
            UpdateData(FALSE);

}