如何删除数组中相同的数字并输出？求解

#include <iostream>
#include <map>
using namespace std;
int main()
{
    map<int,int> mapList;
    int arrayA[] = {3,1,3,4,8,9,9,9};
    int arrayB[] = {3,1,1,9,9,5,7,2};
    int aLen = (int)sizeof(arrayA)/sizeof(int);
    int bLen = (int)sizeof(arrayB)/sizeof(int);
    //mark object between arrayA
    for (int i = 0; i < aLen; i++)
    {
        map<int,int>::iterator it = mapList.find(arrayA[i]);
        if (it == mapList.end())
            mapList[arrayA[i]] = 0;
        else
            mapList[arrayA[i]] = 1;
    }
    //mark object between arrayB
    for (int i = 0; i < bLen; i++)
    {
        map<int,int>::iterator itor = mapList.find(arrayB[i]);
        if (itor == mapList.end())
            mapList[arrayB[i]] = 0;
        else
            mapList[arrayB[i]] = 1;
    }
    //print mapList
    for (map<int,int>::iterator it = mapList.begin(); it != mapList.end(); it++)
        cout<<it->first<<"-----"<<it->second<<endl;
    //delete mark from arrayA
    for (int i = 0; i < aLen; i++)
    {
        map<int,int>::iterator itor = mapList.find(arrayA[i]);
        if (1 == itor->second)//delete
        {
            for (int j = i; j < aLen - 1; j++)
                arrayA[j] = arrayA[j+1];
            aLen--;
        }
    }
    //delete mark from arrayB
    for (int i = 0; i < bLen; i++)
    {
        map<int,int>::iterator itor = mapList.find(arrayB[i]);
        if (1 == itor->second)//delete
        {
            for (int j = i; j < bLen - 1; j++)
                arrayB[j] = arrayB[j+1];
            bLen--;
        }
    }
    //print arrayA and arrayB
    cout<<"arrayA:"<<endl;
    for (int i = 0; i < aLen; i++)
        cout<<arrayA[i]<<" ";
    cout<<"\narrayB:"<<endl;
    for (int i = 0; i < bLen; i++)
        cout<<arrayB[i]<<" ";
    return 0;
}