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#2
fxbszj2012-12-20 20:21
 程序代码：#include <iostream> #include <string> using namespace std; //注意位置 void strcount(const string test); int main(void) { string str1; cout << "enter a string (empty line to terminate input):" << endl; getline(cin, str1); //你这里少个分号 while (str1 != "") { strcount(str1); cout << "enter next line:" << endl; getline(cin, str1); } cout << "done!"; return 0; } void strcount(const string test) { int count = 0; static int total = 0; for (int i = 0; i < test.size(); ++i) { ++count; } cout << "current char is " << count << endl; total += count; cout << "total char is " << total << endl; } 好像这样就可以了，你试试 |
程序代码：#include <iostream>
#include <string>
void strcount(const string test);
int main(void)
{
using namespace std;
string str1;
cout << "enter a string (empty line to terminate input):" << endl;
getline(cin, str1)
while (str1 != "")
{
strcount(str1);
cout << "enter next line:" << endl;
getline(cin, str1);
}
cout << "done!";
return 0;
}
void strcount(const string test)
{
int count = 0;
static int total = 0;
for (int i = 0; i < test.size(); ++i)
{
++count;
}
cout << "current char is " << count << endl;
total += count;
cout << "total char is " << total << endl;
}
#include <string>
void strcount(const string test);
int main(void)
{
using namespace std;
string str1;
cout << "enter a string (empty line to terminate input):" << endl;
getline(cin, str1)
while (str1 != "")
{
strcount(str1);
cout << "enter next line:" << endl;
getline(cin, str1);
}
cout << "done!";
return 0;
}
void strcount(const string test)
{
int count = 0;
static int total = 0;
for (int i = 0; i < test.size(); ++i)
{
++count;
}
cout << "current char is " << count << endl;
total += count;
cout << "total char is " << total << endl;
}
我的意图是这样，输入一行，不管多少个字符，统计输入的字符个数，然后继续输入，统计第二次输入行的字符个数，并且统计前两次输入的总字符数。依次继续，直到输入一个空行，输入结束。只用string类完成，不用数组之类的！代码附上。麻烦来个人指教一下，谢谢了！初学C++感觉有点不适
str.size();