C++的问题：使用基类成员函数的指针产生多态性，对输出结果不理解 - 编程论坛

#2

pangding2012-09-05 00:23

只有静态函数成员才能取地址吧。这样写是不是应该不合法？楼主用的什么编译器？

#3

rjsp2012-09-05 08:03

首先代码语法就是错误的，其次，既然标题说了“……指针产生多态性”，为什么又对输出In Derived不理解？

程序代码：

#include <iostream>
using namespace std;

class base {
public:
    virtual void print() { cout<<"In Base"<<endl; }
};

class derived:public base{
public:
    virtual void print() { cout<<"In Derived"<<endl; }
};

void display( base* pb, void (base::*pf)() ) {
    (pb->*pf)();
}

int main() {
    derived d;
    base* pb = &d;
    void (base::*pf)() = &base::print;
    display( pb, pf );

    return 0;
}

#4

gaoyao4692012-09-05 15:36

#include <iostream>
using namespace std;

class base {
public:
    void print() { cout<<"In Base"<<endl; }
};

class derived:public base{
public:
    void print() { cout<<"In Derived"<<endl; }
};

void display( base* pb, void (base::*pf)() ) {
    (pb->*pf)();
}

int main() {
    derived d;
    base* pb = &d;
    void (base::*pf)() = &base::print;
    display( pb, pf );

    return 0;
}