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#2
zklhp2012-08-25 23:36
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assume cs:code,ds:data,es:table
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97497,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('yaar sumn ne ?? ')
table ends
code segment
start:
mov ax, data
mov ds, ax
mov ax, table
mov es, ax
mov bx, 0
mov si, 0
mov cx, 21 ;初始外循环次数
start0:
mov cx, 8
mov ax, ds:[bx]
mov word ptr es:[bx], ax
add bx, 2
mov ax, ds:[bx]
mov es:[bx], ax
add bx, 2
mov word ptr es:[bx], 20h ;year and space
add bx, 1
mov ax, ds:[bx]
mov es:[bx], ax
add bx, 2
mov dx, ds:[bx]
mov es:[bx], dx
add bx, 2
mov word ptr es:[bx], 20h ;earn and space
add bx, 1
mov si, ds:[bx]
mov es:[bx], si
add bx, 2
mov word ptr es:[bx], 20h ;member and space 20h = ' ' //这句报错。open parenthesis or bracket 想不明白 到底嘛意思
div si ;everyone 's money
add bx, 1
mov es:[bx], ax
add bx, 2
add bx, 1
loop start0
mov ax, 4c00h
int 21h
end start
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97497,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('yaar sumn ne ?? ')
table ends
code segment
start:
mov ax, data
mov ds, ax
mov ax, table
mov es, ax
mov bx, 0
mov si, 0
mov cx, 21 ;初始外循环次数
start0:
mov cx, 8
mov ax, ds:[bx]
mov word ptr es:[bx], ax
add bx, 2
mov ax, ds:[bx]
mov es:[bx], ax
add bx, 2
mov word ptr es:[bx], 20h ;year and space
add bx, 1
mov ax, ds:[bx]
mov es:[bx], ax
add bx, 2
mov dx, ds:[bx]
mov es:[bx], dx
add bx, 2
mov word ptr es:[bx], 20h ;earn and space
add bx, 1
mov si, ds:[bx]
mov es:[bx], si
add bx, 2
mov word ptr es:[bx], 20h ;member and space 20h = ' ' //这句报错。open parenthesis or bracket 想不明白 到底嘛意思
div si ;everyone 's money
add bx, 1
mov es:[bx], ax
add bx, 2
add bx, 1
loop start0
mov ax, 4c00h
int 21h
end start