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#2
hellovfp2012-05-29 10:34
#include <iostream>
#include <string> using namespace std; class message { public: message(){} //定义空的构造函数 message(string nam,string add,string city,int mail):name(nam),address(add),city(city),mail(mail){} int input(); void display(); //输出数据 string amend(); //修改名字 void modify_name(string new_name); string getname() { return name; }; private: string name; string address; string city; int mail; }; int message::input() { cout<<"请输入你的信息:"<<endl; cout<<"请输入您的姓名:"<<endl; cin>>name; cout<<"请输入您的地址:"<<endl; cin>>address; cout<<"请输入您所在的城市:"<<endl; cin>>city; cout<<"请输入您所在城市的邮政编码:"<<endl; cin>>mail; return 0; } void message::display() { cout<<"姓名"<<name<<" "<<"地址:"<<address<<" "<<endl; cout<<"城市:"<<city<<" "<<"邮政编码:"<<mail<<endl; } string message::amend() { message a; cout<<"请输入您要修改的姓名:"<<endl; cin>>name; return 0; } void message::modify_name(string new_name) { this->name = new_name; } int main() { int i,flag=1; message mess[3]; cout<<"请输入三个人的信息:"<<endl; for(i=0;i<3;i++) { mess[i].input(); } cout<<"现在核查您的信息:"<<endl; for(i=0;i<3;i++) { mess[i].display(); } cout<<"请输入你要修改信息的原来人的姓名:"<<endl; string old_name, new_name; cin >> old_name; cout << "修改的姓名:" << endl; cin >> new_name; int found = 0; for( i = 0; i < 3; i++ ) { if(old_name == mess[i].getname()) { cout << "找到该人了" << endl; found = 1; break; } } if(found) mess[i].modify_name(new_name); for(i=0;i<3;i++) { mess[i].display(); } return 0; } |
代码

#include <iostream>
#include <string>
using namespace std;
class message
{
public:
message(){} //定义空的构造函数
message(string nam,string add,string city,int mail):name(nam),address(add),city(city),mail(mail){}
int input();
void display(); //输出数据
string amend(); //修改名字
string getname()
{
return name;
};
private:
string name;
string address;
string city;
int mail;
};
int message::input()
{
cout<<"请输入你的信息:"<<endl;
cout<<"请输入您的姓名:"<<endl; cin>>name;
cout<<"请输入您的地址:"<<endl; cin>>address;
cout<<"请输入您所在的城市:"<<endl; cin>>city;
cout<<"请输入您所在城市的邮政编码:"<<endl; cin>>mail;
return 0;
}
void message::display()
{
cout<<"姓名"<<name<<" "<<"地址:"<<address<<" "<<endl;
cout<<"城市:"<<city<<" "<<"邮政编码:"<<mail<<endl;
}
string message::amend()
{ message a;
cout<<"请输入您要修改的姓名:"<<endl;
cin>>name;
return 0;
}
int main()
{
int i,flag=1;
message mess[3];
cout<<"请输入三个人的信息:"<<endl;
for(i=0;i<3;i++)
{
mess[i].input();
}
cout<<"现在核查您的信息:"<<endl;
for(i=0;i<3;i++)
{
mess[i].display();
}
cout<<"请输入你要修改信息的原来人的姓名:"<<endl;
#include <string>
using namespace std;
class message
{
public:
message(){} //定义空的构造函数
message(string nam,string add,string city,int mail):name(nam),address(add),city(city),mail(mail){}
int input();
void display(); //输出数据
string amend(); //修改名字
string getname()
{
return name;
};
private:
string name;
string address;
string city;
int mail;
};
int message::input()
{
cout<<"请输入你的信息:"<<endl;
cout<<"请输入您的姓名:"<<endl; cin>>name;
cout<<"请输入您的地址:"<<endl; cin>>address;
cout<<"请输入您所在的城市:"<<endl; cin>>city;
cout<<"请输入您所在城市的邮政编码:"<<endl; cin>>mail;
return 0;
}
void message::display()
{
cout<<"姓名"<<name<<" "<<"地址:"<<address<<" "<<endl;
cout<<"城市:"<<city<<" "<<"邮政编码:"<<mail<<endl;
}
string message::amend()
{ message a;
cout<<"请输入您要修改的姓名:"<<endl;
cin>>name;
return 0;
}
int main()
{
int i,flag=1;
message mess[3];
cout<<"请输入三个人的信息:"<<endl;
for(i=0;i<3;i++)
{
mess[i].input();
}
cout<<"现在核查您的信息:"<<endl;
for(i=0;i<3;i++)
{
mess[i].display();
}
cout<<"请输入你要修改信息的原来人的姓名:"<<endl;
这个代码没有写完,我不知道该怎样查找其中一个人的姓名,用栈?或者建立一个名字线性表?对他们进行遍历?
谁能告诉我一个比较简单的思想,求解!
